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Alex73 [517]
3 years ago
6

Does anyone know this? if so would you be kind to help me out?

Mathematics
2 answers:
Neko [114]3 years ago
6 0
The answer is obtuse

Naya [18.7K]3 years ago
3 0
It is a right angle just right angle
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Using symbols write the product of 18 and 7+5
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What is the solution to this equation?<br> -1/5(x+1 1/4)=-2 1/2
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\large\displaystyle\text{$\begin{gathered}\sf -\frac{1}{5}\left(x+1\frac{3}{4}\right)=-2\frac{1}{2}    \end{gathered}$}

Multiply both sides of the equation by 20, the lowest common denominator of 5,4,2.

\large\displaystyle\text{$\begin{gathered}\sf \bf{-4\left(x+\frac{4+3}{4}\right)=-10(2\times2+1)  } \end{gathered}$}

Add 4 and 3 to get 7.

\large\displaystyle\text{$\begin{gathered}\sf \bf{-4\left(x+\frac{7}{4}\right)=-10(2\times2+1)  } \end{gathered}$}

Use the distributive property to multiply −4 times x 4/7.

\large\displaystyle\text{$\begin{gathered}\sf \bf{-4x-4\times\left(\frac{7}{4}\right)=-10(2\times2+1)  } \end{gathered}$}

Multiply −4 by 4/7.

\large\displaystyle\text{$\begin{gathered}\sf \bf{-4x-7=10(2\times2+1) \ \ \to \ \ [Multiply \ 2\times2] }  \end{gathered}$}

\large\displaystyle\text{$\begin{gathered}\sf \bf{-4x-7=10(4+1) \ \ \to \ \ [Add] }  \end{gathered}$}

\large\displaystyle\text{$\begin{gathered}\sf \bf{-4x-7=10\times5 \ \ \to \ \ [Multiply] }  \end{gathered}$}

\large\displaystyle\text{$\begin{gathered}\sf \bf{-4x-7=-50 } \end{gathered}$}

Add 7 to both sides.

\large\displaystyle\text{$\begin{gathered}\sf \bf{-4x=-50+7 \ \ \to \ \ [Add] } \end{gathered}$}

\large\displaystyle\text{$\begin{gathered}\sf \bf{-4x=-43 } \end{gathered}$}

Divide both sides by −4.

\large\displaystyle\text{$\begin{gathered}\sf \bf{x=\frac{-43}{-4} } \end{gathered}$}

The fraction \bf{\frac{-43}{-4}} can be simplified to \bf{\frac{43}{4}} by removing the negative sign from the numerator and denominator.

\large\displaystyle\text{$\begin{gathered}\sf \bf{x=\frac{43}{4} } \end{gathered}$}

simplify

\large\displaystyle\text{$\begin{gathered}\sf \bf{x=10\frac{3}{4} \ \ \to \ \ \ Answer } \end{gathered}$}

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