This is the concept of algebra, let the width be x
height=x-4
length=2x+10
the volume of the box is:
volume=length*width*height
=x(x-4)(2x+10)
expanding the above we get:
(x^2-4x)(2x+10)
=x^2(2x+10)-4x(2x+10)
=2x^3+2x^2-40x=264
solving the above we get real solution will be
x=6
thus we conclude that the width is x=6 inches
length=2*6+10=22 inches
height=x-4=6-4=2 inches
thus the dimension will be:
width=6 inches, length=22 inches, height=2 inches
Did you figure out the answer yet?
Answer:
Step-by-step explanation:
The two photos are attached for the missing information in your question.
Statement: m∠7 and m∠8 are supplementary.
Reason: Linear Pair Theorem
One thing wrong is there is not closing parenthasees after x+1
and also, if you multiply it out, the answer is not 8x^2-8x-16 so the factored form given is worng
the real factored out form is 8(x-2)(x+1)
that person forgot the 8 in the front
Answer:
Question 16
(a) x < 1 : the values of x are smaller than than 1 (e.g. possible values are 0, -1, -2, etc) and since the circle is not shaded it means that 1 isn't a possible value of x
(b) x
-2 : the circle is filled therefore -2 is included in the answer
Question 17
(a) unfilled dot above -2 and arrow pointing to the left
(b) shaded circle above 4 with and arrow pointing to the right →