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nignag [31]
3 years ago
14

A triangle has one side that measures 5 ft, one side that measures 8 ft, and one side that measures 11 ft.

Mathematics
1 answer:
DanielleElmas [232]3 years ago
5 0

an Obtuse angle. Idk what you want.

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These three roots are sufficient to enable us to form a 3rd degree polynomial:

f(x) = (x+4)(x-4)(x-2) = (x^2 - 16)(x-2) = x^3 - 2x^2 - 16x + 32 (answer)

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Fifteen equals s over thirteen
zimovet [89]
Can you restate the question please
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Which one of the following options is true when considering the expansion of
Ilya [14]

Answer:

c The expansion of (x + y)^6 will yield 7 terms

Step-by-step explanation:

(x + y)^6 =

x^6 +6x^5y + 15x^4y^2 + 20x^3y^3 + 15x^2y^4 + 6xy^5 + y^6

so its a no on A

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5 0
2 years ago
Multiply (5x^2 + x-4(x+2)
bagirrra123 [75]

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5x^2-3x-8

Step-by-step explanation:

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4 0
3 years ago
John can jog twice as fast as he can walk. He was able to jog the first mile to his grandmas house but then he got tired and wal
statuscvo [17]

Answer:

  12 mph

Step-by-step explanation:

The relationship between jogging speed and walking speed means the time it takes to walk 4 miles is the same as the time it takes to jog 8 miles. Then the total travel time (0.75 h) is the time it would take to jog 1+8 = 9 miles. The jogging speed is ...

  (9 mi)(.75 h) = 12 mi/h . . . average jogging speed

__

<em>Check</em>

1 mile will take (1 mi)/(12 mi/h) = 1/12 h to jog.

4 miles will take (4 mi)/(6 mi/h) = 4/6 = 8/12 h to walk.

The total travel time is (1/12 +8/12) h = 9/12 h = 3/4 h. (answer checks OK)

_____

<em>Comment on the problem</em>

Olympic race-walking speed is on the order of 7.7 mi/h, so John's walking speed of 6 mi/h should be considered quite a bit faster than normal. The fastest marathon ever run is on the order of a bit more than 12 mi/h, so John's jogging speed is also quite a bit faster than normal. No wonder he got tired.

7 0
3 years ago
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