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vaieri [72.5K]
3 years ago
9

Compute the conditional relative frequency of students with low sugar consumption given that they are low exercise. Round to the

nearest thousandths. A) 0.222 B) 0.438 C) 0.563 D) 0.778
Mathematics
1 answer:
Paraphin [41]3 years ago
4 0

You're a cheater...

I'm gonna answer cause I know you're pass this question.

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abruzzese [7]

Answer:30

Step-by-step explanation: LxW (length x Width) 3x10=30.... Hope this helps... if you break it down then you can write down (10) on your page but the answer is 30

3 0
3 years ago
Functions. Type the correct domain in the box
Mnenie [13.5K]

Function:

y = -2/3 x + 7

Substitute the given values to their respective variable and solve.

x                        y

-6                       3

3                        5

15                      -3

-12                     15

7 0
3 years ago
Scientists predict that there is a 0.8 chance that there will be an earthquake in San Francisco this year. How likely is that th
Firlakuza [10]

Answer:

80%

Step-by-step explanation:

8 0
3 years ago
Two integers will be randomly selected from the sets above, one integer from set A and one integer from set B. What is the proba
Fittoniya [83]

Question:

A = {2, 3, 4, 5}

B = {4, 5, 6, 7, 8}

Two integers will be randomly selected from the sets above, one integer from set A and one integer from set B. What is the probability that the sum of the two integers will equal 9?

A. 0.15

B. 0.20

C. 0.25

D. 0.30

E. 0.33

Answer:

Option B: 0.20 is the probability of the sum of the two integers.

Explanation:

The sample space for selecting 2 numbers is given by

4\times 5 = 20

We need to determine the probability that the sum of two integers will be equal to 9.

Hence, we need to add the two integers from the sets A and B such that their sum will be equal to 9.

Hence, the sets are (2,7),(3,6),(4,5),(5,4)

Thus, the total number of sets whose sum is equal to 9 = 4

The probability that the sum of the two integers will equal 9 is given by

P=\frac{4}{20}

P=\frac{1}{5}

P=0.20

Thus, the probability that the sum of the two integers will equal 9 is 0.20

Hence, Option B is the correct answer.

4 0
3 years ago
The probability distribution of the amount of memory X (GB) in a purchased flash drive is given below. x 1 2 4 8 16 p(x) .05 .10
Rama09 [41]

Answer:

a) E(X) = 6.45

b) E(X^{2} )= 57.25

c) V(X) = 15.648

d) E(3X + 2) = 21.35

e) E(3X^{2} +2) = 173.75

f) V(3X+2) = 140.832

g) E(X+1) = 7.45

h) V(X+1) = 15.648

Step-by-step explanation:

a) E(X) = \sum xP(x)

E(X) = (1*0.05) + (2*0.10) + (4*0.35) + (8*0.40) + (16*0.10)\\E(X) = 6.45

b)

E(X^{2} ) = (1^{2} *0.05) + (2^{2} *0.10) + (4^{2} *0.35) + (8^{2} *0.40) + (16^{2} *0.10)\\  E(X^{2} )= 57.25

c)

V(X) = E(X^{2} ) - (E(X))^{2} \\V(X) = 57.25 - 6.45^{2} \\V(X) = 15.648

d)

E(3X+2) = 3E(X) + 2\\E(3X+2) = (3*6.45) + 2 \\E(3X+2) = 21.35

e)

E(3X^{2} +2) = 3E(X^{2} ) + 2\\E(3X^{2} +2) = (3*57.25) + 2 \\E(3X^{2} +2) = 173.75

f)

V(3X+2) = 3^{2} V(X)\\V(3X+2) = 9*15.648\\V(3X+2) = 140.832

g)

E(X+1) = E(X) + 1\\E(X+1) = 6.45 + 1\\E(X+1) =7.45

h)

V(X+1) = 1^{2} V(X)\\V(X+1) = 15.648

6 0
3 years ago
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