Answer:
0.098 moles
Explanation:
Let y represent the number of moles present
1 mole of Ba(OH)₂ contains 2 moles of OH- ions.
Hence, 0.049 moles of Ba(OH)2 contains y moles of OH- ions.
To get the y moles, we then do cross multiplication
1 mole * y mole = 2 moles * 0.049 mole
y mole = 2 * 0.049 / 1
y mole = 0.098 moles of OH- ions.
1 mole of OH- can neutralize 1 mole of H+
Therefore, 0.098 moles of HNO₃ are present.
Answer:
A mixture of 100. mL of 0.1 M HC3H5O3 and 50. mL of NaOH
Explanation:
The pH of a buffer solution is calculated using following relation

Thus the pH of buffer solution will be near to the pKa of the acid used in making the buffer solution.
The pKa value of HC₃H₅O₃ acid is more closer to required pH = 4 than CH₃NH₃⁺ acid.
pKa = -log [Ka]
For HC₃H₅O₃
pKa = 3.1
For CH₃NH₃⁺
pKa = 10.64
pKb = 14-10.64 = 3.36 [Thus the pKb of this acid is also near to required pH value)
A mixture of 100. mL of 0.1 M HC3H5O3 and 50. mL of NaOH
Half of the acid will get neutralized by the given base and thus will result in equal concentration of both the weak acid and the salt making the pH just equal to the pKa value.
A mile.
For reference, it's about 1,607 or so meters, and 1km is 1,000.
Decomposer, decomposers include fungous, bacteria, worms. They break down trash and bad things and concert it to soil.
Answer:
See below ~
Explanation:
The calculated values of V/n :
⇒ 1.5/0.3 = 5
⇒ 3/0.6 = 5
⇒ 4.5/0.9 = 5
⇒ 6/1.2 = 5
⇒ 7.5/1.5 = 5
1. From this we understand that the calculated values of V/n remain constant, equal to <u>5</u> in this case.
2. The volume-mole graph will be a straight line passing through the origin. (Attached below)