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3 years ago

11

What’s a tripping hazard in Science

2 answers:

attashe74 [19]3 years ago

5 0

Spillages on a tiled floor, a highly polished floor surface, a damp smooth surface with no mat.

Stolb23 [73]3 years ago

4 0

Pencil on the floor or anything on the floor and anything that spilled

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The order of elements in the periodic table is based on of elements in the periodic table is based on

Serhud [2]

The increasing atomic number

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4 years ago

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CH4(g) + H2O(g) CO(g) + 3H2(g)

boyakko [2]

Presuming the arrow is between H20 and CO

On the left there are 2 gas moles.
On the right there are 4 gas moles.

The equilibrium will shift to the side with the most no. He gas moles when pressure is decreased.

Therefore the answer is A, since 4>2.

If you have any questions, feel free to ask

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3 years ago

HELP ILL GIVE U FREE POINTS AND BRAINLEST !! Observe the plate boundary shown here. What type of plate boundary is this? Many ge

Studentka2010 [4]

The answer is B.
You can rule C out because divergent means moving away. Rule out A because there is an oceanic and continental plate, not 2 of the same type. Rule D out for the same reason.

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3 years ago

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Natural gas is stored in a spherical tank at a temperature of 13°C. At a given initial time, the pressure in the tank is 117 kPa

drek231 [11]

Answer:

1. the absolute pressure in the tank before filling = 217 kPa

2. the absolute pressure in the tank after filling = 312 kPa

3. the ratio of the mass after filling M2 to that before filling M1 = 1.44

The correct relation is option c ( $\frac{M_{2} }{M_{1} } = \frac{P_{2} T_{1} }{P_{1} T_{2} }$ )

Explanation:

To find -

1. What is the absolute pressure in the tank before filling?

2. What is the absolute pressure in the tank after filling?

3. What is the ratio of the mass after filling M2 to that before filling M1 for this situation?

As we know that ,

Absolute pressure = Atmospheric pressure + Gage pressure

So,

Before filling the tank :

Given - Atmospheric pressure = 100 kPa , Gage pressure = 117 kPa

⇒Absolute pressure ( p1 ) = 100 + 117 = 217 kPa

Now,

After filling the tank :

Given - Atmospheric pressure = 100 kPa , Gage pressure = 212 kPa

⇒Absolute pressure (p2) = 100 + 212= 312 kPa

Now,

As given, volume is the same before and after filling,

i.e. $V_{1}$ = $V_{2}$

As we know that, P ∝ M

⇒ $\frac{p_{1} }{p_{2} } = \frac{m_{1} }{m_{2} }$

⇒ $\frac{m_{2} }{m_{1} } = \frac{p_{2} }{p_{1} }$

⇒ $\frac{m_{2} }{m_{1} } = \frac{312 }{217 } = 1.4378$ ≈ 1.44

Now, as we know that PV = nRT

As V is constant

⇒ P ∝ MT

⇒ $\frac{P}{T}$ ∝ M

⇒ $\frac{M_{2} }{M_{1} } = \frac{P_{2} T_{1} }{P_{1} T_{2} }$

So, The correct relation is c option.

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3 years ago

How many is too many

Rufina [12.5K]

Answer:

to manyneh nrjwsj

Explanation:

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3 years ago