<h2>
Explanation:</h2>
I am not sure why your teacher isn't asking for the layers, but here is the list of layers;
A -(topsoil) Mostly minerals from parent material with organic matter incorporated. A good material for plants and other organisms to live.
E - (eluviated) - Leached of clay, minerals, and organic matter, leaving a concentration of sand and silt particles of quartz or other resistant materials – missing in some soils but often found in older soils and forest soils.
B - (subsoil) Rich in minerals that leached (moved down) from the A or E horizons and accumulated here.
C - (parent material) The deposit at Earth’s surface from which the soil developed.
R - (bedrock) A mass of rock such as granite, basalt, quartzite, limestone or sandstone that forms the parent material for some soils – if the bedrock is close enough to the surface to weather. This is not soil and is located under the C horizon.
The energy is transferred throughout the rest of the metal by the moving electrons. Metals are described as
malleable (can be beaten into sheets) and ductile (can be pulled out into wires). This is because of the ability of the atoms to roll over each other into new positions without breaking the metallic bond.
Answer:
1. The salt bridge completes the circuit of the voltaic cell to allow the flow of current
2. The porous divider performs the function of a salt bridge, hence a salt bridge is unnecessary in a single-beaker voltaic cell
Explanation:
1. The oxidation and reduction half cells of a voltaic cell are connected by the salt bridge in other to ensure that the internal circuit is electrically neutral, to avoid the rapid reaction to reach equilibrium conditions which affects results in preventing voltage drop in the voltaic cell.
The salt bridge also aids in charge accumulation
2. In a single-beaker voltaic cell with the compartments separated by a porous divider, the function of the porous divider is the same as that of the salt bridge, hence the salt bridge is unnecessary.
Answer:
bro if you read it it will tell you what it is
( just telling you to read it man or women)
Explanation:
Answer:
643g of methane will there be in the room
Explanation:
To solve this question we must, as first, find the volume of methane after 1h = 3600s. With the volume we can find the moles of methane using PV = nRT -<em>Assuming STP-</em>. With the moles and the molar mass of methane (16g/mol) we can find the mass of methane gas after 1 hour as follows:
<em>Volume Methane:</em>
3600s * (0.25L / s) = 900L Methane
<em>Moles methane:</em>
PV = nRT; PV / RT = n
<em>Where P = 1atm at STP, V is volume = 900L; R is gas constant = 0.082atmL/molK; T is absolute temperature = 273.15K at sTP</em>
Replacing:
PV / RT = n
1atm*900L / 0.082atmL/molK*273.15 = n
n = 40.18mol methane
<em>Mass methane:</em>
40.18 moles * (16g/mol) =
<h3>643g of methane will there be in the room</h3>