All categories

3 years ago

Which is a pure substance (A) Mixture (B) Solution (C) Molecule

2 answers:

8 0

C. Molecule is a pure substance. It may be 2 or more atoms binding together via covalent bonding (I.e. the sharing of electrons). The bonding of two or more atoms from the same element forms stable molecules.
The bonding of two different atoms or more will result in a completely new substance as compared to the original substances of atoms.

Mixtures, from the name itself, are being mixed with several solutions, where one part of it is soluble, and the other part is insoluble.
●For e.g., sand and seawater being put together forms a mixture, where sea water is water and salt (soluble together) and sand (insoluble with water and salt).

Solutions may be 2 or more substances being mixed together which are soluble.
● For the sea water example above, sea water is the solution, since salt can be desolved in water (i.e. the solute).

Hope this helps! :)

raketka [301]3 years ago

4 0

It's C, I believe

good luck

You might be interested in

Which property of the water molecule causes two water molecules to be attracted to each other?

Mamont248 [21]

Hydrogen/Hydrogen bonds

4 0

3 years ago

Choose all answers that apply

Alexeev081 [22]

Answer

Rapid Combustion

Explanation:

An explosion is a combustion and a quick reaction, That makes it rapid

3 0

3 years ago

Read 2 more answers

I’m having hard time to understand can someone answer it and explain it

tekilochka [14]

Number #2 is joule

In the SI system the unit of heat is the joule. The calorie was defined so that the heat capacity of water was equal to one.The heat capacity of a substance is the amount of heat required to raise the temperature of a defined amount of pure substances by one degree.

Number #3 is Endothermic

Why? I can't explain. I Just left class where they were just explaining that.

7 0

3 years ago

Which living thing would u expect to find in a swamp

stich3 [128]

Alligators, Crocodiles, Anacondas, Beavers, Fish , Frogs and MANY more.

~mathnerdz

6 0

3 years ago

Two methanol-water mixtures are contained in separate tanks. The first mixture contains 40.0 wt% methanol and the second contain

RoseWind [281]

Answer:

$M_{per}= 52.86$

$W_{per}=47.14$

Explanation:

<u>First mixture</u>:

40 wt% methanol - 60 wt% water 200 kg

$m_{met1}=200 kg * 0.4= 80 kg$

$m_{wat1}=200 kg * 0.6= 120 kg$

<u>Second mixture</u>:

70 wt% methanol - 30 wt% water 150 kg

$m_{met2}=150 kg * 0.7= 105 kg$

$m_{wat2}=150 kg * 0.3= 45 kg$

Final mixture:

$m_{metF=80 kg + 105 kg= 185 kg$

$m_{watF}=120 kg + 45 = 165 kg$

$M_{per}=\frac{185 kg}{185 kg + 165 kg}*100= 52.86$

$W_{per}=\frac{165 kg}{185 kg + 165 kg}*100=47.14$

If, the compositions are constant, the only variables are the mass of each mixture used in the final one, so there can be only one independent balance.

8 0

3 years ago