Check the picture below.
how do we know? well, notice h(t), starts off at 12, up up up reaches 47.84 then down down down, which is pretty much the trajectory of a flying object, by the time it gets to 44, is still going down.
now, let's look at g(t), starts off at 10, and goes up up up, never down, by the time it gets to 41, is still going up,
so at second 2, h(t) is 44 and going down, g(t) is 41 and going up, at 2.2 h(t) is 40.16, and g(t) is 44.1, between that lapse, h(t) became 44, 43, 42, 41, in the same lapse g(t) became 41, 42, 43, 44, so somewhere in those values h(t) = g(t).
what does the solution mean? It's the seconds or the instant lapse when the first cannon ball was at the same height as the second cannonball.
Answer:
Step-by-step explanation:
If two lines are parallel then they will have the same slope. So all you need to do is find the slope of the line that joins the two given points. You can use the slope formula
. You can also graph the two points and use rise over run. 
Given:
ML = 2.3
Angle L = 70 degrees
What we want to find:
MN = x
Use the sine rule
Make sure your calculator is in degree mode
sin(angle) = opposite/hypotenuse
sin(70) = x/2.3
2.3*sin(70) = x
x = 2.3*sin(70)
x = 2.16129302780759
x = 2.2
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Answer: 2.2
Answer: 13, 14
Step-by-step explanation:
I counted
Answer:
6x2+3x+1
Step-by-step explanation:
6x2+3x+1