Answer:
<em> Length of guy wire is 590.6 ft</em>
Step-by-step explanation:
The complete question is
A radio transmission tower is 210 feet tall. How long should a guy wire be if it is to be attached 8 feet from the top and is to make an angle of 20° with the ground. Give your answer to the nearest tenth of a foot.
height of tower = 210 ft
8 ft fro the top leaves 210 - 8 = 202 ft to the ground
This is an angle of elevation problem
the opposite is 202 ft
hypotenuse = ?
angle is 20°
using sin ∅ = opp/hyp
sin 20° = 202/hyp
0.342 = 202/hyp
hyp = 202/0.342 = <em>590.6 ft this is the length of the guy wire</em>
Answer:
-4x + 5y
Step-by-step explanation:
-1/6 x 24 x simplifies to -1 times 4x, which is -4x. -1/6 times -30y simplifies to -1 times -5y, which is 5y.
Since the total is 42 divide by two since they are the same length so it would be 21
Answer:
no
Step-by-step explanation:
it is not strait
Hope this works!
Answer:
length, width, and height are (b+2), (b-2), (b+3)
Step-by-step explanation:
Doing what the problem statement tells you to do, you get ...
(b^3 +3b^2) -(4b +12)
= b^2(b +3) -4(b +3) . . . factor each pair of terms
= (b^2 -4)(b +3) . . . write as a product
= (b -2)(b +2)(b +3) . . . use the factoring of the difference of squares
The three factors are (b-2) , (b+2) , and (b+3). We have no clue as to how to associate those with length, width, and height. We just know these are the dimensions of the box.
