Ask question

Ask question

All categories

steposvetlana [31]

3 years ago

7

Pls help I need help plsss

1 answer:

cupoosta [38]3 years ago

4 0

Whats up? What do you need help with

You might be interested in

Plz help me with number 1. Plz!!!!

snow_tiger [21]

Answer:

Your screwed

Step-by-step explanation:

3 0

3 years ago

Which of the following are solutions to the equation below 4x^2+20x+25=49

KATRIN_1 [288]

( 2x +5)^2 =4

2x+5=2

2x=-3

X=-3/2

4 0

4 years ago

Read 2 more answers

Can someone please help me. I will give you brainliest, I’m struggling bad...

zhenek [66]

Step-by-step explanation:

as the other guy say it a for real

3 0

3 years ago

Women are recommended to consume 1700 calories per day. You suspect that the average calorie intake is larger for women at your

Pachacha [2.7K]

Answer:

theres only a? wheres the rest?

6 0

3 years ago

How to solve this linear equation step by step please

mote1985 [20]

$\bf \cfrac{3}{c^2-4c}-\cfrac{9}{2c^2+3c}=\cfrac{2}{2c^2-5c-12}\\\\\\ 
\begin{cases}
c^2-4c=&c(c-4)\\
2c^2+3c=&c(2c+3)\\\\
2c^2-5c-12=
&(2c+3)(c-4)
\end{cases}\\\\
-------------------------------\\\\
\textit{therefore, our LCD for the \underline{left-side} will have to be }\underline{c(c-4)(2c+3)}\\\\
-------------------------------\\\\$

$\bf \cfrac{3}{c(c-4)}-\cfrac{9}{c(2c+3)}=\cfrac{2}{(2c+3)(c-4)}
\\\\\\
\cfrac{3(2c+3)-9(c-4)}{c(c-4)(2c+3)}=\cfrac{2}{(2c+3)(c-4)}
\\\\\\
\cfrac{6c+9-(9c-36)}{c(c-4)(2c+3)}=\cfrac{2}{(2c+3)(c-4)}
\\\\\\
\cfrac{6c+9-9c+36}{1}=\cfrac{2[c(c-4)(2c+3)]}{(2c+3)(c-4)}
\\\\\\
-3c+45=2c\implies 45=5c\implies \cfrac{45}{5}=c\implies 9=c$

7 0

3 years ago