Answer:
a.v=u+v/2
a.v=s/t
combining two equation we get,
u+v/2=s/t
(u+v)t/2=s
(u+v)t/2=s
{u+(u+at)}t/2=s
(u+u+at)t/2=s
(2u+at)t/2=s
2ut+at^2/2=s
2ut/2+at^2/2=s
UT +1/2at^2=s
proved
a=v-u/t
at=v-u
u+at=v
Answer: 109.4 mm
Explanation: <u>Distance</u> is a scalar quantity and it is the measure of how much path there are between two locations. It can be calculated as the product of velocity and time: d = vt
The separation between the two steamrollers is 105 mm or 0.105 m. They collide to each other at the middle of the separation:
location of collision =
= 0.0525 m
To reach that point, both steamrollers will have spent



t = 0.04375 s
The fly is travelling with speed of 2.5 m/s. So, at t = 0.04375 s:
d = 2.5*0.04375
d = 0.109375 m
Until it is crushed, the fly will have traveled 109.4 mm.
6x2=12m
6x18=108
12m+108
Simplified: m+9 bc 12/12 and 108/12
Answer:
D=387.28m
Explanation:
At the moment where the toss is made
, so we need both equations:
For the red car:
With initial speed of 0 and acceleration of 6.12m/s^2.
For the green car:
With
and Xo = 200m
Since both positions will be the same:
Solving for t:
t1 = -5.8s and t1 =11.25s
Replacing t = 11.25 on either equation to find the displacement:
