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4 years ago

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Consider the expression below. Assume m is an integer. 6m(2m + 18) Enter an expression in the box that uses the variable m and m

akes the equation true. (Simplify your answer completely. If no expression exists, enter DNE.)

1 answer:

Anika [276]4 years ago

8 0

6x2=12m
6x18=108
12m+108
Simplified: m+9 bc 12/12 and 108/12

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When jumping straight down, you can be seriously injured if you land stiff-legged. One way to avoid injury is to bend your knees

choli [55]

Answer:

a) F = 1.26 10⁵ N, b) F = 2.44 10³ N, c) F_net = 1.82 10³ N directed vertically upwards

Explanation:

For this exercise we must use the relationship between momentum and momentum

I = Δp

F t = p_f -p₀

a) It asks to find the force

as the man stops the final velocity is zero

F = 0 - p₀ / t

the speed is directed downwards which is why it is negative, therefore the result is positive

F = m v₀ / t

F = 63.5 7.89 / 3.99 10⁻³

F = 1.26 10⁵ N

b) in this case flex the knees giving a time of t = 0.205 s

F = 63.5 7.89 / 0.205

F = 2.44 10³ N

c) The net force is

F_net = Sum F

F_net = F - W

F_net = F - mg

let's calculate

F_net = 2.44 10³ - 63.5 9.8

F_net = 1.82 10³ N

since it is positive it is directed vertically upwards

6 0

3 years ago

A string with a mass density of 3 * 10^-3 kg/m is under a tension of 380 N and is fixed at both ends. One of its resonance frequ

Delvig [45]

Answer:

(a) the fundamental frequency of this string is 65 Hz

(b) the harmonics of the given frequencies are third and fourth respectively.

(c) the length of the string is 2.74 m

Explanation:

Given;

mass density of the string, μ = 3 x 10⁻³ kg/m

tension of the string, T = 380 N

resonating frequencies, 195 Hz and 260 N

For the given resonant frequencies;

$195 = \frac{n}{2l} \sqrt{\frac{T}{\mu} } ---(1)\\\\260 = \frac{n+1}{2l} \sqrt{\frac{T}{\mu} } ---(2)\\\\divide \ (2) \ by (1)\\\\\frac{260}{195} = \frac{n+1 }{n} \\\\260n = 195(n+1)\\\\260 n = 195 n + 195\\\\260n - 195n = 195\\\\65n = 195\\\\n = \frac{195}{65} \\\\n = 3$

(c) From any of the equations, solve for Length of the string (L);

$195 = \frac{n}{2l} \sqrt{\frac{T}{\mu} } \\\\195 = \frac{3}{2l}\sqrt{\frac{380}{3\times 10^{-3}} } \\\\l = \frac{3}{2\times 195}\sqrt{\frac{380}{3\times 10^{-3}} }\\\\l = 2.74 \ m$

(a) the fundamental frequency is calculated as;

$f_o = \frac{1}{2l} \sqrt{\frac{T}{\mu} } \\\\f_o = \frac{1}{2\times 2.74} \sqrt{\frac{380}{3\times 10^{-3} } }\\\\f_o = 65 \ Hz$

(b) harmonics of the given frequencies;

the first harmonic (n = 1) = f₀ = 65 Hz

the second harmonic (n = 2) = 2f₀ = 130 Hz

the third harmonic (n = 3) = 3f₀ = 195 Hz

the fourth harmonic (n = 4) = 4f₀ = 260 Hz

Thus, the harmonics of the given frequencies are third and fourth respectively.

7 0

3 years ago

A car traveling at 40 m/s starts to decelerate steadily. It comes to a complete stop in 5 seconds. What is its acceleration? m/s

SCORPION-xisa [38]

Acceleration =

   (change of speed) / (time for the change).

Change of speed = (speed at the end) - (speed at the beginning)

      =    ( zero ) - (40 m/s)

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Acceleration = (-40 m/s) / (5 seconds)

   = -8 m/s² .

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A soccer ball is kicked from point Pi at an angle above a horizontal field. The ball follows an ideal path before landing on the

Nutka1998 [239]

Answer:

A. The horizontal velocity vector points to the right & equals v cos Î¸.

Explanation:

The motion describes a parabolic path, where the horizontal speed is constant and the horizontal velocity vector always points to the right and equals v*cos Î¸.

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3 years ago

A material is nonmagnetic and gaseous and does not conduct heat or electricity. It will, however, react with other elements. It

topjm [15]

Answer:

The correct option is: Nonmetal

Explanation:

Non-metals are the chemical elements that are generally present in the gaseous state at room temperature and have low electrical and thermal conductivity. These elements are non-magnetic and tend to have low density, boiling point and melting point. Non-metals have high electronegativity and ionization energy and react by sharing or gaining electrons from the other elements.

<u>Therefore, the given material is most likely a non-metal.</u>

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4 years ago