1answer.
Ask question
Login Signup
Ask question
All categories
  • English
  • Mathematics
  • Social Studies
  • Business
  • History
  • Health
  • Geography
  • Biology
  • Physics
  • Chemistry
  • Computers and Technology
  • Arts
  • World Languages
  • Spanish
  • French
  • German
  • Advanced Placement (AP)
  • SAT
  • Medicine
  • Law
  • Engineering
Hunter-Best [27]
4 years ago
13

You hold a spherical salad bowl 50 cm in front of your face with the bottom of the bowl facing you. The salad bowl is made of po

lished metal with a 44 cm radius of curvature.
(a) Where is the image of your 5.0-cm-tall nose located?
(b) What are the image’s size, orientation, and nature (real or virtual)?
Physics
1 answer:
nataly862011 [7]4 years ago
4 0

Answer:

a) q = 39.29 cm ,  b)   h ’= - 3.929 cm  the image is inverted  and REAL

Explanation:

For this exercise we will use the equation of the constructor

          1 / f = 1 / p + 1 / q

where f is the focal length of the salad bowl, p and q are the distance to the object and the image

The metal salad bowl behaves like a mirror, so its focal length is

           f = R / 2

           f = 44/2

           f = 22 cm

a) Suppose that the distance to the object is p = 50 cm, let's find the distance to the image

           1 / q = 1 / f  - 1 / p

           1 / q = 1/22 - 1/50

           1 / q = 0.0254

            q = 39.29 cm

b) to calculate the size of the image we use the equation of magnification

           m = h’/ h = - q / p

            h ’= - q / p h

            h ’= - 39.29 / 50 5

            h ’= - 3.929 cm

the negative sign means that the image is inverted

as the rays of light pass through the image this is REAL

You might be interested in
How do mountain building and volcanoes relate to plate motion at convergent boundaries
Naddika [18.5K]
Mountains and volcanoes are built at convergent plates in a boundary which pushes up the earth.
5 0
4 years ago
What is the acceleration, in meters per second squared, of a 2,000,000-kilogram NASA rocket with an applied force of 20,000,000
liubo4ka [24]

Answer:

10m/s^2

Explanation:

Force = mass x acceleration

Acceleration = force/ mass

= 20000000/2000000

=10m/s^2

3 0
3 years ago
Which is the force of repulsion between two positivity-charged particles?
Yuki888 [10]

Since they are both positively charged, then the force would in fact be repulsion, because they are both the same. If you were to have one positively charged, and one negatively charged, then they would go towards eachother.

I hope this helps, if you need help on this question or any other questions, just ask. I am here to help.

3 0
3 years ago
Read 2 more answers
The L-ft ladder has a uniform weight of W lb and rests against the smooth wall at B. θ = 60. If the coefficient of static fricti
Colt1911 [192]

This question is incomplete, the complete question;

The L-ft ladder has a uniform weight of W lb and rests against the smooth wall at B. θ = 60. If the coefficient of static friction at A is μ = 0.4.

Determine the magnitude of force at point A and determine if the ladder will slip. given the following; L = 10 FT, W = 76 lb

Answer:

- the magnitude of force at point A is 79.1033 lb

- since FA < FA_max; Ladder WILL NOT slip

Explanation:

Given that;

∑'MA = 0

⇒ NB [Lsin∅] - W[L/2.cos∅] = 0

NB = W / 2tan∅ -------let this be equation 1

∑Fx = 0

⇒ FA - NB = 0

FA = NB

therefore from equation 1

FA = NB = W / 2tan∅

we substitute in our values

FA = NB = 76 / 2tan(60°) = 21.9393 lb

Now ∑Fy = 0

NA - W = 0

NA = W = 76 lb

Net force at A will be

FA' = √( NA² + FA²)

= √( (W)² + (W / 2tan∅)²)

we substitute in our values

FA' = √( (76)² + (21.9393)²)

= √( 5776 + 481.3328)

= √ 6257.3328

FA' = 79.1033 lb

Therefore the magnitude of force at point A is 79.1033 lb

Now maximum possible frictional force at A

FA_max = μ × NA

so, FA_max = 0.4 × 76

FA_max = 30.4 lb

So by comparing, we can easily see that the actual friction force required for keeping the the ladder stationary i.e (FA) is less than the maximum possible friction available at point A.

Therefore since FA < FA_max; Ladder WILL NOT slip

5 0
3 years ago
) A steel guitar string with a diameter of 1.00 mm is stretched between supports 80.0 cm apart. The temperature is 0.0°C. (a) Fi
ladessa [460]

Answer: a. Mass per unit length =0.0245kg/m

b. Tension =2.45x10^-8N

C. Tension = 2.45 x10^-8N

Fundamental frequency =200Hz

Explanation:

7 0
4 years ago
Other questions:
  • Can someone help me? My homework is due on Friday and I really need help. Does the speedometer on a car give you the instantaneo
    8·1 answer
  • Marcus drove his Honda Prelude for 4 hours at a rate of 55 miles per hour. How far did he travel?
    8·2 answers
  • What is the name of the german scientist that proposed the theory of continental drift
    11·1 answer
  • How does a transmission electron microscope work?
    11·1 answer
  • When an object is in orbit, it is falling at the same rate at which the Earth is curving. Please select the best answer from the
    7·1 answer
  • The potential on the surface of a sphere (radius R) is given by <img src="https://tex.z-dn.net/?f=V%20%3D%20V_0%20cos%282%20%5Ct
    15·1 answer
  • A sample of gas has a volume of 42 L at a pressure of 200 kPa and a temperature of 30^ * C . What would be the volume, if the pr
    9·1 answer
  • I punch myself really hard. Does that make me strong or weak?
    13·2 answers
  • A car increases its speed from 11.1 meters per second to 24.2 meters per second in 5.0 seconds. What is the average acceleration
    7·1 answer
  • If the magnitude of the sum of two vectors is greater than the magnitude of either vector, then?
    9·1 answer
Add answer
Login
Not registered? Fast signup
Signup
Login Signup
Ask question!