Answer:
Step-by-step explanation:
H(3,2) & J(4, 1)
K(-2,-4) & M(-1 , -5)
![Slope =\dfrac{-5-[-4]}{-1-[-2]}\\\\=\dfrac{-5+4}{-1+2}\\\\= \dfrac{-1}{1}\\\\\\= -1](https://tex.z-dn.net/?f=Slope%20%3D%5Cdfrac%7B-5-%5B-4%5D%7D%7B-1-%5B-2%5D%7D%5C%5C%5C%5C%3D%5Cdfrac%7B-5%2B4%7D%7B-1%2B2%7D%5C%5C%5C%5C%3D%20%5Cdfrac%7B-1%7D%7B1%7D%5C%5C%5C%5C%5C%5C%3D%20-1)
Line HJ and KM have same slopes. So, they are parallel
Answer:
26
Step-by-step explanation:
2*3*5-3(-2)+5(-2)
6*5+6-10
30+6-10
36-10
26
We can create equations to solve this.
2.50p + 1.50m = 29.50
p + m = 15
Solve for a variable in the 2nd equation and use the substitution method to solve.
p + m = 15
Subtract p to both sides:
m = -p + 15
Plug in -p + 15 for m in the first equation.
2.50p + 1.50(-p + 15) = 29.50
Distribute:
2.50p - 1.50p + 22.50 = 29.50
Combine like terms:
p + 22.50 = 29.50
Subtract 22.50 to both sides:
p = 7
Now plug this into any of the two equations and solve for the other variable.
p + m = 15
7 + m = 15
Subtract 7 to both sides:
m = 8
So he purchased 7 pineapples and 8 mangos.
Answer:
Step-by-step explanation:
x = 0.8 + 0.2y
There is no hard and fast rule to select the class width. It largely depends on our application.However, one thing that should be kept in mind is that the number of classes should neither to be too low nor too high. So keeping this thing in mind, the class width is select.
The range of the data is = Maximum- Minimum = 96 - 11 = 85
10 classes will be most suited for this data.
The class width for each data can be calculated as:
Class Width = Range / Number of Classes = 85/10 = 8.5
Class width is always rounded to nearest next integer. So the class width will be 9 in this case.
So, the best value of class width or interval width for the given data will be 9.
