3 years ago

4 sweets cost 28 p altogether how much do 7 sweets cost?

2 answers:

4 0

4 sweets cost 28p altogether

28÷4=7p for each sweet

If each sweet costs 7p, then 7 sweets would be multiplied by 7

7×7p=49p

7 sweets cost 49p

iris [78.8K]3 years ago

4 0

Divide 28 by 4 then u get 7. then u multiply 7 sweets by 7 and you get 49.
so the answer is one 1 sweet costs 7$ = 7 sweets cost 49$

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beks73 [17]

The result of expanding the trigonometry expression $\sin^2(\theta) * (1 + \cos(\theta))$ is $cos^0(\theta) + \cos(\theta) - \cos^2(\theta) - \cos^3(\theta)$

<h3>How to evaluate the expression?</h3>

The expression is given as:

$\sin^2(\theta) * (1 + \cos(\theta))$

Express $\sin^2(\theta)$ as $1 - \cos^2(\theta)$ .

So, we have:

$\sin^2(\theta) * (1 + \cos(\theta)) = (1- \cos^2(\theta)) * (1 + \cos(\theta))$

Open the bracket

$\sin^2(\theta) * (1 + \cos(\theta)) = 1 + \cos(\theta) - \cos^2(\theta) - \cos^3(\theta)$

Express 1 as cos°(Ф)

$\sin^2(\theta) * (1 + \cos(\theta)) = cos^0(\theta) + \cos(\theta) - \cos^2(\theta) - \cos^3(\theta)$

Hence, the result of expanding the trigonometry expression $\sin^2(\theta) * (1 + \cos(\theta))$ is $cos^0(\theta) + \cos(\theta) - \cos^2(\theta) - \cos^3(\theta)$

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MariettaO [177]

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