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2 years ago

What is the GCF of 36 and 90

Mathematics

2 answers:

ELEN [110]2 years ago

8 0

The greatest common factor is 18

hichkok12 [17]2 years ago

5 0

The greatest common factor is 18.

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the lateral surface area of right circular cylinder is 120 pi cm squared and the circumference is 12 cm find the height

konstantin123 [22]

Answer:

h=31.4 cm

Step-by-step explanation:

A=lateral surface area

c=circumference

h=height

A= c*h

solving for h we get:

h=A/c=120pi/12=10pi

6 0

2 years ago

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Find the slope of -1:9 0:5 1:1,<br> -4/1<br> -1/4<br> 1/4<br> 4/1

IRISSAK [1]

Answer:

1/4

Step-by-step explanation:

A P E X

4 0

2 years ago

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Find the equation of the line that passes through both (5,1) and (8,-2)

Georgia [21]

Let $f(x) = ax+b$ be the line that passes through both points.

We know that $f(5) = 1$ and $f(8) = -2$ . So:

$\begin{cases}5a+b = 1 \\ 8a+b = -2\end{cases}$

Solving the system, we get that a= -1 and b = 6.

So the line is equal to $f(x) = 6-x$ .

5 0

2 years ago

Find the equation of the line that passes through the points : (4 , -1 ) and (0 , -3)

Sergio [31]

Answer:

B. y= 1/2 x - 3

Step-by-step explanation:

base equation: y= mx+ b

slope(m) equation: $\frac{y_{2}-y_{2} }{x_{2} -x_{1} }$

y2= -1 y1= -3

x2= 4 x1= 0

$\frac{-1 - (-3)}{4-0} =\frac{2}{4} = \frac{1}{2}$

y- intercept: -3

found by taking the y from (0,-3)

3 0

2 years ago

25 POINTS AND BRAINLIEST PLEASE HELP ASAP

dexar [7]

M is a midpoint of BC so:

$M=\left(\dfrac{\boxed{2}\boxed{a}+a}{\boxed{2}},\dfrac{\boxed{0}+b}{2}\right)=\left(\dfrac{\boxed{3}\boxed{a}}{\boxed{2}},\dfrac{\boxed{b}}{\boxed{2}}\right)$

Length of MA:

$MA=\sqrt{\left(\dfrac{\boxed{3}a}{2}\boxed{-}\boxed{0}\right)^2+\left(\dfrac{\boxed{b}}{2}\boxed{-}\boxed{0}\right)^2}=\\\\\\=
\sqrt{\left(\dfrac{\boxed{3}a}{\boxed{2}}\right)^2+\left(\dfrac{b}{2}\right)^2}=\sqrt{\dfrac{\boxed{9}a^2}{\boxed{4}}+\dfrac{\boxed{b}^2}{\boxed{4}}}$

Length of NB:

$NB=\sqrt{\left(\dfrac{a}{2}\boxed{-}\boxed{2}a\right)^2+\left(\dfrac{b}{2}\boxed{-}\boxed{0}\right)^2}=\\\\\\=\sqrt{\left(\dfrac{a}{2}\boxed{-}\dfrac{\boxed{4}\boxed{a}}{2}\right)^2+\left(\dfrac{b}{2}-\boxed{0}\right)^2}=\\\\\\
\sqrt{\left(\dfrac{-3a}{2}\right)^2+\left(\dfrac{b}{\boxed{2}}\right)^2}=\sqrt{\dfrac{\boxed{9}a^2}{\boxed{4}}+\dfrac{\boxed{b}^2}{\boxed{4}}}$

5 0

3 years ago

Read 2 more answers