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arsen [322]
3 years ago
11

Work out (8x10^-3) x (2x10^-4)​

Mathematics
2 answers:
Fynjy0 [20]3 years ago
5 0

Answer:

(8 × 10^-3)× ( 2× 10 ^-4)

reorder the terms

You will get

(8 × 2) ( 10^ -3 × 10^-4)

Multiply

16 ( 10^ -3 × 10^-4)

Use the rules of indices

a^ b × a^ c = a^b+c

16(10^-3-4)

16(10^-7)

= 16 × 10^-7 or 1.6 × 10^-6 or 0.0000016

Hope this helps.

love history [14]3 years ago
3 0

Answer:

1.6 \times 10^{-6}

Step-by-step explanation:

(8 \times 10^{-3}) \times (2 \times 10^{-4})

8 \times 2 \times 10^{-3} \times 10^{-4}

16 \times 10^{-3+(-4)}

16 \times 10^{-3-4}

16 \times 10^{-7}

1.6 \times 10^{-6}

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4x^2+3x+4

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3x^2+2x+3+x^2+x+1=4x^2+3x+4

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6 0
3 years ago
Solve for x use the completing the square method x^2+6x=5
Mrac [35]

Answer:

x_{1} =-3 +\sqrt{14} \\\\x_{2} =-3 -\sqrt{14}

Step-by-step explanation:

x^{2}+6x-5=0

we divide the coefficient of the X by half :

in this case: 6/2 = 3 , then we do the following

The result obtained is raised to square power:  3^2=9

we sum and subtract by 9 to maintain the balance of the equation:

x^{2}+6x+9-9-5=0

we have:

(x+3)^{2}-9-5=0

(x+3)^{2} = 14

lets apply square root on both sides of the equation:

\sqrt{(x+3)^{2}}=\sqrt{14}

we know:

\sqrt{a^{2}} = abs(a)

so we have:

abs(x+3)=\sqrt{14}

from where two solutions are obtained

x_{1} + 3 =\sqrt{14} \\\\x_{2} + 3 =-\sqrt{14}

finally we have:

x_{1} =-3 +\sqrt{14} \\\\x_{2} =-3 -\sqrt{14}

5 0
3 years ago
Read 2 more answers
Micheal took his brother to the movies. Micheal paid regular price, but it cost $2 less for his brother at the child price. It c
iren [92.7K]

It cost $5 for his brother's ticket.

Step-by-step explanation:

Let,

Micheal's ticket price= x

His brother ticket price = y

According to given statement;

x+y=12    Eqn 1

y = x-2    Eqn 2

Putting value of y from Eqn 2 in Eqn 1

x+(x-2)=12\\x+x-2=12\\2x=12+2\\2x=14\\

Dividing both sides by 2;

\frac{2x}{2}=\frac{14}{2}\\x=7

Putting x=7 in Eqn 2

y=7-2\\y=5

It cost $5 for his brother's ticket.

Keywords: linear equation, substitution method

Learn more about linear equations at:

  • brainly.com/question/2747595
  • brainly.com/question/2750627

#LearnwithBrainly

8 0
3 years ago
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