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Kruka [31]
3 years ago
12

I NEED HELP ASAP!!!!

Mathematics
1 answer:
Degger [83]3 years ago
4 0
I hope this helps you!

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MATH HELP!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!
steposvetlana [31]
I believe the answer is 9

This is because in order to take out a three, There would need to be 2 3's and 9 is 3x3, so the answer is 9.
3 0
3 years ago
Pls help being timed and I don’t understand
shepuryov [24]

Answer:

f ( -2 ) = 30

g ( -2 ) = 3

Step-by-step explanation:

when it says f(x) and then has f(-2) - you fill in all x's in the equation with -2.. like this:

f(x) = -7(-2-2) +2                         g(x) = 2(-2)^2 -5

f(x) = -7(-4) +2                             g(x) = 2(4) -5

f(x) = 28 + 2                                g(x) = 8 - 5

f(x) = 30                                      g(x) = 3

hope this helps!!

6 0
3 years ago
In order for maximum growth of orange trees in a grove, the farmer must plant the trees exactly 6’3” apart to ensure the best su
juin [17]

Answer:

I dont no :)

Step-by-step explanation:

lol

4 0
3 years ago
What is the following simplified product? Assume x greater-than-or-equal-to 0
nlexa [21]

Answer:

  10x^4\sqrt{6}+x^3\sqrt{30x}-10x^4\sqrt{3}-x^3\sqrt{15x}

Step-by-step explanation:

Remove perfect squares from under the radicals.

  (\sqrt{10x^4}-x\sqrt{5x^2})(2\sqrt{15x^4}+\sqrt{3x^3})\\\\=(\sqrt{10x^4})(2\sqrt{15x^4}) +(\sqrt{10x^4})(\sqrt{3x^3}) -(x\sqrt{5x^2})(2\sqrt{15x^4}) -(x\sqrt{5x^2})(\sqrt{3x^3})\\\\=2\sqrt{150x^8}+\sqrt{30x^7}-2x\sqrt{75x^6}-x\sqrt{15x^5}\\\\=\boxed{10x^4\sqrt{6}+x^3\sqrt{30x}-10x^4\sqrt{3}-x^3\sqrt{15x}}

_____

The applicable rules of exponents are ...

  (x^a)(x^b) = x^(a+b)

  √(a^2) = a . . . . . . . for a > 0

  (√a)(√b) = √(ab)

5 0
3 years ago
Read 2 more answers
Which of the following parametric equations are equivalent to the polar equation r=3 cos theta
Allushta [10]
To solve the problem you must know that to change from Cartesian to polar coordinates you must write:
 x = rcos (θ)
 Where "r" is the radius
 Likewise y = rsin (θ)
 Therefore, in the expression r = 3cos (θ) one can write r as:
 r = x / cos (θ)
 So:
 x / cos (θ) = 3cos (θ)
 x = 3cos ^ 2 (θ)
 The same for y ...
 y = rsin (θ)
 y = 3cos (θ) sin (θ).

  Finally the correct answer is option 2.
 x = 3cos ^ 2 (θ) y = 3cos (θ) sin (θ).
5 0
3 years ago
Read 2 more answers
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