The equation ofa line that passes throug (x1,y1) and has s slope of m is
y-y1=m(x-x1)
given
point is (-1,-3) and slope=4
y-(-3)=4(x-(-1)) or
y+3=4(x+1)
B is the answer
Answer:
m(ABC) = 218°
Step-by-step explanation:
The measure of any arc with end points of an inscribed angle = 2 × inscribed angle
Inscribed angle = m<AMC = 109°
Intercepted arc = m(ABC)
Therefore,
m(ABC) = 2 × 109°
m(ABC) = 218°
<u>Answer-</u>
<em>The probability that a randomly selected recipe does not contain sugar, given that it contains salt is 22.4%</em>
<u>Solution-</u>
The given table in the link shows the relative frequencies of recipes that contains sugar and salt, or contains at least one of those ingredients, or contains neither of those ingredients.
We have to find the conditional probability that the recipe doesn't contain sugar, given that it contains salt.
We know that, the conditional probability of occurrence of A given that B occurs is,



Putting these values,

Answer:
The height of the building is 
Step-by-step explanation:
see the attached figure to better understand the problem
we know that
In the right triangle ABC

we have

substitute and solve for BC


Find the height of the building
The height of the building (h) is equal to

Answer:
-4/3 = y
Step-by-step explanation:
-1/2 = 3/8y
Multiply each side by 8/3 to isolate y
-1/2 * 8/3 = 3/8y * 8/3y
-8/6 =y
-4/3 = y