Well, you only listed three pieces so far. But I can already see a
pattern emerging from those three.
Of course, the next piece might return to 1-1/2 inches. I mean,
the pattern can't just keep on going and increasing forever or
Cody would eventually wind up with pieces that are a mile long.
It must eventually return to 1-1/2 inches and start over from there.
From the first piece to the second one, and from the second one
to the third one, the increase is 5/16 inch both times. So if the
pattern is more than three pieces long before it starts over from
1-1/2, then the next piece is
(2-1/8 + 5/16) = (2-2/16 + 5/16) = 2-7/16 inches .
Answer:
11 weeks
Step-by-step explanation:
5÷1/2=10
10+1=11
Sorry if I'm wrong
Answer:
There are only 3 differences perform
Step-by-step explanation:
I. If x is negative, y is negative then the answer is possitive
eg. x is -2, y is -3
-2 × -3 = 6
II. If x is negative, y is positive then the answer is negative
eg. x is -1, y is 2
-1 × 2 = -2
III. If x is possitive, y is possitive then the answer is positive
eg. x is 2, y is 5
2 × 5 = 10
Alt. No matter how long x, y, z, a, b there always apply only 3 rules above. Multiply or Devide are the same rule.
Ask me for anything :D
To solve the problem, do the problem in the parenthesis () then do your answer with the numbers outside the ().
(8-3) = 5 x 3 = 15
(6 + 4) = 10 / 2 = 5
(6 - 4) = 2 / 2 = 1
(6 x 4) = 24 / 2 = 3
Um... part of the (6 4) doesn't make sense... What goes between the numbers? Plus, minus, multiply or division sign? Please tell.
But, I already got you started off and I'll let you figure out the rest. (If you can not figure out the rest, please tell me what sign is between the 6 and 4 in (6 4) and then I'll give you the answer and a better explanation.)
I hope this helps! :D
Two ratios that are equivalent are the same in value. We call these equivalent ratios. To find an equivalent ratio multiply or divide both of the numbers by a common number (or same number), this would be the exact same when finding equivalent fractions as well.
