Answer:
1 hour
Step-by-step explanation:
I find these easiest to work by considering the initial difference in distance and the speed at with that gap is closing.
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The gap is 15 miles, the distance the first ship is from harbor when the second ship starts.
The rate of closure is the difference in the speeds of the two ships:
60 mph -45 mph = 15 mph
Then the closure time is ...
time = distance/speed
time = (15 mi)/(15 mi/h) = 1 h
It will take the second ship 1 hour to catch up to the first ship.
#11
Each roll is 9' long,
length of each roll = 9' * (12"/foot) = 108"
Each ribbon piece = 15", so number of ribbons per roll
=108/15=7 with 3" left over, which is assumed not possible to be joined with other pieces.
Therefore, with 5 rolls, there are 7*5=35 pieces of ribbon, with 5 pieces or 3" left over.
The primeter is the outside p=2+2 +3+1+1 so the primiter is 9
I think maybe 0.3 then 2 1/2 and then 15
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