Answer:
B
Step-by-step explanation:
1/2 * 1 * 2 1/2 = 1 1/4
if theres 8 half unit cubes per unit cube, then we can take the two numbers given to us and divide them by 1 1/4 or 1.25 in decimal
9514 1404 393
Answer:
- n = (s/m) -r
- n = (s -mr)/m
Step-by-step explanation:
1. Undo the operations done to n, in reverse order. Here, n has r added and the sum is multiplied by m. First we divide by m, then we subtract r.
m(n+r) = s . . . given
n +r = s/m . . . divide by m
n = (s/m) -r . . . subtract r
__
2. Eliminate the parentheses, then proceed as above. Subtract the added term, then divide by the coefficient of n.
m(n+r) = s
mn +mr = s . . . eliminate parentheses
mn = s -mr . . . subtract the added term
n = (s -mr)/m . . . divide by the coefficient of n
Answer:
h = 13.333 +693.333/r
Step-by-step explanation:
For h hours, Brandee's pay will be ...
pay = 40r +(h -40)(1.5r) . . . . 40 hours at rate r + overtime (h-40) hours at 1.5r
pay = 40r +1.5hr -60r . . . . . eliminate parentheses
pay = 1.5hr -20r . . . . . . . . . . collect terms
Solving for h, we have ...
pay +20r = 1.5hr . . . . . . . . . . add 20r
h = (pay +20r)/(1.5r) . . . . . . . . divide by 1.5r
For the given pay of 800 +240 = 1040, we have ...
h = (1040 +20r)/(1.5r)
h = 13.333 +693.333/r . . . . . simplify to 2 terms
_____
<em>Additional comments</em>
You need to know r to find the number of hours Brandee worked. She got paid $800 for a presumed 40-hours of regular time, so made r = $20 per hour. The above formula will tell you she worked 48 hours in the pay period.
Well
3x^2+6x-x-2
So the answer would be
3x^2+5x-2
Answer:
Step-by-step explanation:
A. y-Intercept of ƒ(x)
ƒ(x) = x² - 4x + 3
f(0) = 0² - 4(0) + 3 = 0 – 0 + 3 = 3
The y-intercept of ƒ(x) is (0, 3).
If g(x) opens downwards and has a maximum at y = 3, it's y-intercept is less than (0, 3).
Statement A is TRUE.
B. y-Intercept of g(x)
Statement B is FALSE.
C. Minimum of ƒ(x)
ƒ(x) = x² - 4x + 3
a = 1; b = -4; c = 3
The vertex form of a parabola is
y = a(x - h)² + k
where (h, k) is the vertex of the parabola.
h = -b/(2a) and k = f(h)
h = -b/2a = -(-4)/(2×1 = 2
k = f(2) = 2² - 4×2 + 3 =4 – 8 +3 = -1
The minimum of ƒ(x) is -1. The minimum of ƒ(x) is at (2, -1).
Statement C is FALSE.
D. Minimum of g(x)
g(x) is a downward-opening parabola. It has no minimum.
Statement D is FALSE
