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gizmo_the_mogwai [7]
4 years ago
9

Function f is represented by the equation shown.

Mathematics
1 answer:
aliya0001 [1]4 years ago
4 0

Answer:

\boxed{\text{A.  The y-intercept of function f is greater than the y-intercept of function g}}

Step-by-step explanation:

A. y-Intercept of ƒ(x)

ƒ(x) = x² - 4x + 3

f(0) = 0² - 4(0) + 3 = 0 – 0 + 3 = 3

The y-intercept of ƒ(x) is (0, 3).

If g(x) opens downwards and has a maximum at y = 3, it's y-intercept is less than (0, 3).

Statement A is TRUE.

B. y-Intercept of g(x)

Statement B is FALSE.

C. Minimum of ƒ(x)

ƒ(x) = x² - 4x + 3

a = 1; b = -4; c = 3

The vertex form of a parabola is

y = a(x - h)² + k

where (h, k) is the vertex of the parabola.

h = -b/(2a) and k = f(h)

h = -b/2a = -(-4)/(2×1 = 2

k = f(2) = 2² - 4×2 + 3 =4 – 8 +3 = -1

The minimum of ƒ(x) is -1. The minimum of ƒ(x) is at (2, -1).

Statement C is FALSE.

D. Minimum of g(x)

g(x) is a downward-opening parabola. It has no minimum.

Statement D is FALSE

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40% = 19.2 acres

20% = 9.6 acres

10% = 4.8 acres

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5.03+13.7+108

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What set of transformations could be applied to rectangle ABCD to create A″B″C″D″? 'Rectangle formed by ordered pairs A at negat
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Answer:

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Step-by-step explanation:

We have,

Rectangle ABCD with co-ordinates A(-4,2), B(-4,1), C(-1,1) and D(-1,2).

It is transformed to a new rectangle A'B'C'D' with co-ordinates A'(-4,-2), B'(-4,-1), C'(-1,-1) and D'(-1,-2).

The graph of both the triangles is shown below.

we see that,

The rectangle ABCD is reflected about y-axis and then rotated 180° to obtain A'B'C'D'.

                     Reflected about y-axis                     Rotation of 180°

A= (-4,2)                     (4,2)                                              A'= (-4,-2)

B= (-4,1)                      (4,1)                                                B'= (-4,-1)

C= (-1,1)                       (1,1)                                                 C'= (-1,-1)

D= (-1,2)                      (1,2)                                                 D'= (-1,-2)

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