If ƒ(x ) = x^2 + 1, find ƒ(a + 1).
a^2 + 2
a^2+a+1
a^2+2a+2
2 answers:
I'm pretty sure that this is how it goes
If ƒ(x ) = x^2 + 1, find ƒ(a + 1).
x=(a+1) so u replace x to get this:
f(a+1) = (a+1)^2+1
If you square "a" it just becomes a^2 and "1" squared is just "1"
1+1=2
Answer: a^2+2a+2
If ƒ(x ) = x^2 + 1, find ƒ(a + 1).
x=(a+1) so u replace x to get this:
f(a+1) = (a+1)^2+1
If you square "a" it just becomes a^2 and "1" squared is just "1"
1+1=2
Answer: a^2+2a+2
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