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ANTONII [103]
3 years ago
13

For which equation would n = 0 not be a solution?

Mathematics
1 answer:
4vir4ik [10]3 years ago
5 0
For the first equation n + 4 = 5, because 0 + 4 is not equal 5
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Suppose that g(x) varies inversely with (x) and g(x) = 0.2 when x=0.1. What is g(x) when x=1.6?
mestny [16]
Since g(x) varies with x, therefore:
g(x) = k/x where k is a constant.

So, first we need to get k. We are given that g(x) = 0.2 when x = 0.1
Substitute with these values to get k as follows:
g(x) = k/x
0.2 = k/0.1
k = 0.2*0.1 = 0.02

Now, the equation became:
g(x) = 0.02 / x

We need to get the g(x) when x = 1.6
Therefore, we will substitute with x in the equation and calculate the corresponding g as follows:
g(x) = 0.02 / 1.6
g(x) = 0.0125
6 0
3 years ago
Read 2 more answers
Help me please. I really need it, explain to me how it is done too, I’d really really appreciate that.
DanielleElmas [232]
All angles in a triangle add up to 180 so 180 - 60 = 120 then 180 - 155 = 25 then 25+65 = 90 that is the remaining angle but finally 180 - 90 = 90 is the missing angle
3 0
3 years ago
HELP PLEASE I DONT KNOW HOW TO DO THIS PLS HELP!!!
insens350 [35]
16 represents the # of small pair of gloves and 2 is the # of large pair of gloves
5 0
3 years ago
Cual es la mediana de los datos en un estudio​
seraphim [82]

Answer:

La mediana de un conjunto de números es el número del medio del conjunto (después de que los números se hayan ordenado de menor a mayor).

Step-by-step explanation:

Digamos que tienes estos números, 4, 7, 2, 9, 7, 6 y 4. primero, los pones en orden de menor a mayor (2, 4, 4, 6, 7, 7, 9), y luego usted determina qué número está en el medio, que es 6.

3 0
3 years ago
The scale drawing of a building has a width of 4 inches and a height of 8 inches. If the width of the actual building is 32 feet
kirill115 [55]
Hello!

First you have to find the scale

32 / 4 = 8

To get the actual building you multiply the scale building by 8 and change the units to feet

8 * 8 = 64ft

The answer is 64ft

Hope this helps!
6 0
3 years ago
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