The value of the equation for "a" in terms of x and y is (y+1)/(x-3)²
Step-by-step explanation:
The equation is a classic example of a binomial equation in 2 variables and one constant.
Given- y=a(x-3)²-1
Transferring 1 to the left-hand side
y+1=a(x-3)²
We can opt for various method from now on like we can divide both the sides by (x-3)² or we can possibly transfer (x-3)² to the left-hand side to get the value of "a" in terms of "x" and "y"
∴ Opting for the first method, we get
(y+1)/(x-3)²=a
Thus the required value of "a" in terms of the variable "x" and "y" is as follows-
a= (y+1)/(x-3)²
Answer: 45
Step-by-step explanation:
30 times (3/2)
30 times 3 equals 90.
90 divided 2 equals 45.
Answer:
4455587111*#654..++4756##8008/+.+=///=!558887425
Answer:
There were 40 2-point questions and 9 3-point questions.
Step-by-step explanation:
To solve this situation, write two equations. One for the number of questions and one for the number of points.
Let x be the number of 2 point questions.
Let y be the number of 5 point questions.
x + y = 49
Now since x are each worth 2 points, the total points is 2x.
And since y are each worth 5 points, the total points is 5y.
So 2x + 5y = 125. Substitute one of the equations into the other to solve for the variables.
x + y = 49 becomes x = 49 - y. Substitute it.
2(49-y) + 5y = 125
98 - 2y + 5y = 125
98 + 3y = 125
3y = 27
y = 9
Substitute y = 9 back into the equation x = 49 - y to find x.
x = 49 - 9
x = 40
*dabs frantically* :) :) :)
