(-2,+<img src="https://tex.z-dn.net/?f=%5Csqrt%7Bx%7D" id="TexFormula1" title="\sqrt{x}" alt="\sqrt{x}" align="absmiddle" class=

What is the area of the trapezoid if the bottom base is 4x-5 and the top is 6x+3 with both sides being -5x+10?

Salsk061 [2.6K]

Step-by-step explanation:

Area=(a+b)/2 x h

a=6x+3

b=4x-5

h=-5x+10

Area= -25x^2+55x-10

6 0

3 years ago

Find the domain and range of the function graphed. Assume that the function has arrows that extend the graph past the screen sho

3241004551 [841]

Put the dot on the 5 and than go down 4 i think this is right but i might be wrong sorry if i am

5 0

3 years ago

Which expression was factored completely using the GCF, if the original expression was

Lerok [7]

Answer:

4x(x+2)

Step-by-step explanation:

4 0

3 years ago

Read 2 more answers

(3-4i)(6i+7)-(2-3i)

Sergeu [11.5K]

Answer:

43-7i

Step-by-step explanation:

We are given the expression:

$\displaystyle \large{(3 - 4i)(6i + 7) - (2 - 3i)}$

First, expand 3-4i in 6i+7. To expand binomial with binomial, first we expand 3 in 6i+7 then expand -4i in 6i+7.

$\displaystyle \large{[(3 \cdot 6i) + (3 \cdot 7) + ( - 4i \cdot 6i) + ( - 4i \cdot 7)]- (2 - 3i)} \\ \displaystyle \large{[18i + 21 - 24 {i}^{2} - 28i]- (2 - 3i)}$

Now combine like terms.

$\displaystyle \large{[ - 10i+ 21 - 24 {i}^{2} ]- (2 - 3i)}$

Imaginary Unit

$\displaystyle \large{i = \sqrt{ - 1} } \\ \displaystyle \large{ {i}^{2} = - 1 }$

Therefore:-

$\displaystyle \large{[ - 10i+ 21 - 24 ( - 1) ]- (2 - 3i)} \\ \displaystyle \large{[ - 10i+ 21 + 24]- (2 - 3i)} \\ \displaystyle \large{[ - 10i+ 45]- (2 - 3i)}$