Solve each quadratic equation by completing the square. 6x2 – 28x = - 16

Mathematics

1 answer:

Nataly_w [17]4 years ago

4 0

Answer:

<h3> There is no real solution</h3>

Step-by-step explanation:

$6x^2-28x = - 16\\\\6x^2-28x + 16=0\\\\3x^2-7x+8=0\\\\9x^2-21x+24=0\\\\(3x)^2-2\cdot3x\cdot\frac72+(\frac72)^2-(\frac72)^2+24=0\\\\(3x-\frac72)^2-\frac{49}4+24=0\\\\(3x-\frac72)^2-12\frac{1}4+24=0\\\\(3x-\frac72)^2+12\frac{3}4=0\\\\(3x-\frac72)^2=-12\frac{3}4$

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Evaluate ab + 3c when a=-6, b=-2, and c=5

ra1l [238]

Do it step by step
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A negative times a negative is positive. (-)(-)=+
12+3(5)
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4 years ago

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valentinak56 [21]

Answer:

a. 6

b. 144

Step-by-step explanation:

a. 25% of 24 is 6

b. 24 x 6 = 144

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3 years ago

A case a 24 pairs of same king of sports shoes cost a little more than $800. Explain whether $28 per pair is a good estimate of

bixtya [17]

Total number of pairs = 24 pairs.

Total cost of 24 pairs = $800 approximately.

Cost of each pair = $\frac{Total \ cost \ of\ 24 \ pairs }{Number \ of \ pairs }$

Plugging values in the above formula, we get

Cost of each pair = $\frac{800}{24}$

If we divide 800 by 24, we get 33.33 approximately.

But in the given problem, estimated cost is given $28 per pair.

If we subtract 33.33-28, we get $5.33.

So, the estimated cost is $5.33 each pair less than the actual cost of each pair.

Therefore, $28 per pair is not a good estimate of the price.

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4 years ago

I need help finishing a question. I used the explanation function on the program, but it didn't specify what to do to get the fi

leva [86]

I would compute sqrt(1 + 160pi^2) first to get approximately 39.75093337

Add this to 1 and we have 40.75093337

Then divide over 2pi to get a final approximate result of 6.48571248

So x = 6.48571248 is one approximate solution

In short, I computed $\frac{1+\sqrt{1+160\pi^2}}{2\pi}$ only focusing on the plus for now.

----------------------

If you were to compute $\frac{1-\sqrt{1+160\pi^2}}{2\pi}$ you should get roughly -6.167402596 as your other solution. Each solution can then be plugged into the original equation to check if you get 0 or not. You likely won't land exactly on 0 but you'll get close enough.