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Lady_Fox [76]
3 years ago
9

How would you graph the solution to -5w + 9 = 14 on a number line?

Mathematics
1 answer:
kirill [66]3 years ago
3 0

Answer:

Draw a point one unit to the left of zero.

Step-by-step explanation:

The equation of unknown w is given here and we have to solve it and then we have to check how to draw the point w on the number line.

Now, the equation is - 5w + 9 = 14

⇒ - 5w = 5

⇒ w = - 1

Now, we know that in a number line if we move right from zero then this is a positive direction and if we move left from zero then this direction is the negative direction.

Hence, to plot w = - 1, we must draw a point one unit to the left of zero. (Answer)

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9b+5=23 solve equation
yarga [219]

Steps to solve:

9b + 5 = 23

~Subtract 5 to both sides

9b = 18

~Divide 9 to both sides

b = 9

Best of Luck!

5 0
3 years ago
Solve for x.<br> 144°<br> 18 degrees<br> 30 degrees<br> 48 degrees<br> 120 degrees
disa [49]

Answer:

<h2><u><em>x = 18 °</em></u></h2>

Step-by-step explanation:

you have a rotation angle of 360 °, take out the known values ​​(360 ° -90 ° -144 ° = 126), 144 ° is part of a flat angle of 180 °, from 180 ° remove 144 and you have 36 °, they are opposite angles therefore the same. therefore 360 ​​- 144 - 90 - 36 - 36 = 54.

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4 0
3 years ago
Which are the solutions of x^2 = –11x + 4?
strojnjashka [21]

This is a quadratic equation, i.e. an equation involving a polynomial of degree 2. To solve them, you must rearrange them first, so that all terms are on the same side, so we get

x^2 + 11x - 4 = 0

i.e. now we're looking for the roots of the polynomial. To find them, we can use the following formula:

x_{1,2} = \frac{-b\pm\sqrt{b^2-4ac}}{2}

where x_{1,2} is a compact way to indicate both solutions x_1 and x_2, while a,b,c are the coefficients of the quadratic equation, i.e. we consider the polynomial ax^2+bx+c.

So, in your case, we have a=1,\ \ b=11,\ \ c=-4

Plug those values into the formula to get

x_{1,2} = \frac{-11\pm\sqrt{121+16}}{2} = \frac{-11\pm\sqrt{137}}{2}

So, the two solutions are

x_1 = \frac{-11+\sqrt{137}}{2}

x_2 = \frac{-11-\sqrt{137}}{2}

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