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3 years ago

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Jacob takes 7 classes, each 50.00 minutes long every day for the 5 day school week. How many hours per week does he spend in cla

ss? your answer should have for significant figures round your answer to two decimal places

1 answer:

Zina [86]3 years ago

5 0

Answer: He spends 29.17 hours per week

Explanation:

1 class = 50mins

7 classes = 7 x 50mins = 350mins

For 5 days in a week, we have

5 x 350mins = 1750mins

Converting to hours, we have

1750 /60 = 29.17 hours

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In a particular electroplating process, the metal being plated has a +4 charge. If 861.8 C of charge pass through the cell, how

Xelga [282]

Answer: $2.2326\times 10^{-3}$ moles

Explanation:

We are given:

Moles of electron = 1 mole

According to mole concept:

1 mole of an atom contains $6.022\times 10^{23}$ number of particles.

We know that:

Charge on 1 electron = $1.6\times 10^{-19}C$

Charge on 1 mole of electrons = $1.6\times 10^{-19}\times 6.022\times 10^{23}=96500C$

The metal being plated has a +4 charge, thus the equation will be:

$M^{4+}+4e^-\rightarrow M$

$4\times 96500C$ of electricity deposits = 1 mole of metal

Thus 861.8 C of electricity deposits = $\frac{1}{4\times 96500}\times 861.8=2.2326\times 10^{-3}$ moles of metal

Thus $2.2326\times 10^{-3}$ moles of metal should be plated

3 0

3 years ago

Just make up some random stuff and send it to me on discord Spawn#5567

dybincka [34]

Is there a question that needs to be answered

3 0

4 years ago

Calculate the percent of each component in the mixture. Show your calculations. Circle final answers.

Colt1911 [192]

Answer:

See Explanation

Explanation:

The question is incomplete; as the mixtures are not given.

However, I'll give a general explanation on how to go about it and I'll also give an example.

The percentage of a component in a mixture is calculated as:

$\%C_E = \frac{E}{T} * 100\%$

Where

E = Amount of element/component

T = Amount of all elements/components

Take for instance:

In $(Ca(OH)_2)$

The amount of all elements is: (i.e formula mass of $(Ca(OH)_2)$ )

$T = 1 * Ca + 2 * H + 2 * O$

$T = 1 * 40 + 2 * 1 + 2 * 16$

$T = 74$

The amount of calcium is: (i.e formula mass of calcium)

$E = 1 * Ca$

$E = 1 * 40$

$E = 40$

So, the percentage component of calcium is:

$\%C_E = \frac{E}{T} * 100\%$

$\%C_E = \frac{40}{74} * 100\%$

$\%C_E = \frac{4000}{74}\%$

$\%C_E = 54.05\%$

The amount of hydrogen is:

$E = 2 * H$

$E = 2 * 1$

$E = 2$

So, the percentage component of hydrogen is:

$\%C_E = \frac{E}{T} * 100\%$

$\%C_E = \frac{2}{74} * 100\%$

$\%C_E = \frac{200}{74}\%$

$\%C_E = 2.70\%$

Similarly, for oxygen:

The amount of oxygen is:

$E = 2 * O$

$E = 2 * 16$

$E = 32$

So, the percentage component of oxygen is:

$\%C_E = \frac{E}{T} * 100\%$

$\%C_E = \frac{32}{74} * 100\%$

$\%C_E = \frac{3200}{74}\%$

$\%C_E = 43.24\%$

5 0

3 years ago

CH4+ 2O2>CO2 + 2H2O

Karolina [17]

Answer:

The given reaction is combustion reaction heat is also produced.

Explanation:

Chemical equation:

CH₄ + 2O₂ → CO₂ + 2H₂O

The given reaction is combustion of methane. When methane burn it produced water and carbon dioxide. Heat is also produced.

The given reaction followed the law of conservation of mass.

Law of conservation of mass:

According to the law of conservation mass, mass can neither be created nor destroyed in a chemical equation.

Explanation:

This law was given by french chemist Antoine Lavoisier in 1789. According to this law mass of reactant and mass of product must be equal, because masses are not created or destroyed in a chemical reaction.

CH₄ + 2O₂ → CO₂ + 2H₂O

There are equal number of carbon hydrogen and oxygen atoms present on both side of equation. So it follow the law of conservation of mass.

4 0

4 years ago

Find the sum of - 1 /5 and reciprocal of 6 /11

Bess [88]

<em>Answer:</em>

<h2><em>4</em><em>9</em><em>/</em><em>3</em><em>0</em></h2>

<em>Solution</em><em>,</em>

<em>Reciprocal</em><em> </em><em>of </em><em>6</em><em>/</em><em>1</em><em>1</em><em>=</em><em>1</em><em>1</em><em>/</em><em>6</em>

<em>Now,</em>

<em>-</em><em>1</em><em>/</em><em>5</em><em>+</em><em>1</em><em>1</em><em>/</em><em>6</em>

<em>=</em><em>-</em><em>1</em><em>*</em><em>6</em><em>+</em><em>1</em><em>1</em><em>*</em><em>5</em><em>/</em><em>3</em><em>0</em>

<em>=</em><em>-</em><em>6</em><em>+</em><em>5</em><em>5</em><em>/</em><em>3</em><em>0</em>

<em>=</em><em>4</em><em>9</em><em>/</em><em>3</em><em>0</em>

<em>Hope </em><em>it</em><em> helps</em>

<em>Good </em><em>luck</em><em> on</em><em> your</em><em> assignment</em>

7 0

4 years ago