Ask question

Ask question

All categories

3 years ago

14

A real estate company wants to build a parking lot along the side of one of its buildings using 800 feet of fence. If the side a

long the building needs no fence, what are the dimensions of the largest possible parking lot?

1 answer:

Elden [556K]3 years ago

3 0

Answer:

80,00 $ft^{2}$

Step-by-step explanation:

According to my research, the formula for the Area of a rectangle is the following,

$A = L*W$

Where

A is the Area
L is the length
W is the width

Since the building wall is acting as one side length of the rectangle. We are left with 1 length and 2 width sides. To maximize the Area of the parking lot we will need to equally divide the 800 ft of fencing between the <u>Length and Width.</u>

800 / 2 = 400ft

So We have 400 ft for the length and 400 ft for the width. Since the width has 2 sides we need to divide 60 by 2.

400/2 = 200 ft

Now we can calculate the maximum Area using the values above.

$A = 400ft*200ft$

$A = 80,000ft^{2}$

So the Maximum area we are able to create with 800 ft of fencing is 80,00 $ft^{2}$

I hope this answered your question. If you have any more questions feel free to ask away at Brainly.

Read more on Brainly.com - brainly.com/question/12953427#readmore

You might be interested in

What is the answer please.... need help

mina [271]

Answer:

$f\left(x\right)=x^3-6x^2+3x+10$ is the function of the least degree has the real coefficients and the leading coefficients of 1 and with the zeros -1, 5, and 2.

Step-by-step explanation:

Given the function

$f\left(x\right)=x^3-6x^2+3x+10$

As the highest power of the x-variable is 3 with the leading coefficients of 1.

So, it is clear that the polynomial function of the least degree has the real coefficients and the leading coefficients of 1.

solving to get the zeros

$f\left(x\right)=x^3-6x^2+3x+10$

$0=x^3-6x^2+3x+10$ ∵ $f(x)=0$

as

$Factor\:x^3-6x^2+3x+10\::\:\left(x+1\right)\left(x-2\right)\left(x-5\right)=0$

so

$\left(x+1\right)\left(x-2\right)\left(x-5\right)=0$

Using the zero factor principle

if $ab=0\:\mathrm{then}\:a=0\:\mathrm{or}\:b=0\:\left(\mathrm{or\:both}\:a=0\:\mathrm{and}\:b=0\right)$

$x+1=0\quad \mathrm{or}\quad \:x-2=0\quad \mathrm{or}\quad \:x-5=0$

$x=-1,\:x=2,\:x=5$

Therefore, the zeros of the function are:

$x=-1,\:x=2,\:x=5$

$f\left(x\right)=x^3-6x^2+3x+10$ is the function of the least degree has the real coefficients and the leading coefficients of 1 and with the zeros -1, 5, and 2.

Therefore, the last option is true.

8 0

2 years ago

If you need $8000 to travel to Europe after you graduate in 4 year. How much would your monthly deposits need to be if your acco

lina2011 [118]

$\bf \qquad \qquad \textit{Future Value of an ordinary annuity}\\
\left. \qquad \qquad \right.(\textit{payments at the end of the period})
\\\\
A=pymnt\left[ \cfrac{\left( 1+\frac{r}{n} \right)^{nt}-1}{\frac{r}{n}} \right]$

$\bf \qquad 
\begin{cases}
A=
\begin{array}{llll}
\textit{accumulated amount}\\
\end{array}\to &
\begin{array}{llll}
8000
\end{array}\\
pymnt=\textit{periodic payments}\\
r=rate\to 5\%\to \frac{5}{100}\to &0.05\\
n=
\begin{array}{llll}
\textit{times it compounds per year}\\
\textit{monthly, thus twelve}
\end{array}\to &12\\
t=years\to &4
\end{cases}$

$\bf 8000=pymnt\left[ \cfrac{\left( 1+\frac{0.05}{12} \right)^{12\cdot 4}-1}{\frac{0.05}{12}} \right]
\\\\\\
\cfrac{8000}{\left[ \frac{\left( 1+\frac{0.05}{12} \right)^{12\cdot 4}-1}{\frac{0.05}{12}} \right]}=pymnt\implies \cfrac{8000}{\frac{\left( \frac{241}{240} \right)^{48}-1}{\frac{1}{240}}}=pymnt
\\\\\\
\cfrac{8000}{53.0148852}\approx pymnt\implies 150.9010152318\approx pymnt$

6 0

3 years ago

Factorise fully the following 2x+8

kakasveta [241]

Answer:

it cant be solved

Step-by-step explanation:

please a brainliest please

7 0

3 years ago

Read 2 more answers

The sum of 1/6,2/3, and 1/4 is

Bumek [7]

¹³/₁₂

<h3>Further explanation</h3>

<u>Given:</u>

$\boxed{ \ \frac{1}{6} + \frac{2}{3} + \frac{1}{4} = ? \ }$

A fraction represents part of a whole.
A fraction consists of a numerator and a denominator. i.e., $\boxed{ \ \frac{numerator}{denominator} \ }$ .
The numerator = the number of equal parts of a whole.
The denominator = the total number of parts that make up said whole.

From the problems above, the denominator or the bottom numbers are still different. We use the Least Common Multiple (or LCM) to equalize the denominator.

Multiples of 3: $\boxed{ \ \{3, 6, 9, 12, 15, ... \} \ }$
Multiples of 4: $\boxed{ \ \{4, 8, 12, 16, ... \} \ }$
Multiples of 6: $\boxed{ \ \{6, 12, 18, ... \} \ }$

Hence, the LCM for 3, 4, and 6 is 12.

We change the denominator for each fraction to 12.

$\boxed{ \ \frac{1}{6} \rightarrow \frac{multiply \ by \ 2}{multiply \ by \ 2} \rightarrow \frac{2}{12} \ }$

$\boxed{ \ \frac{2}{3} \rightarrow \frac{multiply \ by \ 4}{multiply \ by \ 4} \rightarrow \frac{8}{12} \ }$

$\boxed{ \ \frac{1}{4} \rightarrow \frac{multiply \ by \ 3}{multiply \ by \ 3} \rightarrow \frac{3}{12} \ }$

Then we continue adding fractions.

$\boxed{ \ \frac{1}{6} + \frac{2}{3} + \frac{1}{4} = \frac{2}{12} + \frac{8}{12} + \frac{3}{12} \ }$

$\boxed{ \ \frac{1}{6} + \frac{2}{3} + \frac{1}{4} = \boxed{ \ \frac{13}{12} \ } \ }$

Thus, the result is $\boxed{ \ \frac{13}{12} \ or \ 1\frac{1}{12}\ }$

<h3>Learn more</h3>

²/₇m - ¹/₇= ³/₁₄ solve step by step brainly.com/question/4853649
100 is 1/10 of what? brainly.com/question/96535
Mr. Frye distributed his money equally among his 4 children for their weekly allowance brainly.com/question/13174288#

Keywords: the sum of ¹/₆, ²/₃, and ¹/₄, fraction, adding, numerator, denominator, still different, LCM

6 0

3 years ago

Read 2 more answers

I will mark u brainalist

melisa1 [442]

Answer:

1) Positive

2) Undefined

3) Negative

4) Zero

<h2><u>Hope This Helped!</u></h2>

3 0

2 years ago