3 years ago

What is an equation of the line that passes through the point (-4,3) and has a slope of -1?

Mathematics

1 answer:

vlabodo [156]3 years ago

8 0

Y=mx+b
plug in the point
3=-1*-4+b
3=4+b
b=-1
y=-1x-1

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Find the value of m. (-3/4)-⁴×(-3/4)-¹¹ = (-3/4)^m

tatiyna

Answer:

m = - 15

Step-by-step explanation:

Using the rule of exponents

$a^{m}$ × $a^{n}$ = $a^{(m+n)}$ , then

$(-\frac{3}{4}) ^{-4}$ × $(-\frac{3}{4}) ^{-11}$ = $(-\frac{3}{4}) ^{m}$ , that is

$(-\frac{3}{4}) ^{(-4-11)}$ = $(-\frac{3}{4}) ^{m}$

$(-\frac{3}{4}) ^{-15}$ = $(-\frac{3}{4}) ^{m}$

Equating exponents gives

m = - 15

4 0

3 years ago

Describe and correct any error a student may have made when solving the equation

Lady_Fox [76]

Answer:

The student made an error during the distributive property in the second step where they multiplied 0.15 by -0.2 to equal -0.3 when it should have been -0.03.

Step-by-step explanation:

$0.15(y-0.2)=2-0.5(1-y)\\0.15y-0.03=2-0.5+0.5y\\0.15y-0.03=1.5+0.5y\\100(0.15y-0.03)=100(1.5+0.5y)\\15y-3=150+50y\\15y-3-15y-150=150+50y-15y-150\\-153=35y\\-\frac{153}{35}=y$