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chubhunter [2.5K]
3 years ago
13

Find the sum of the interior angle measures of a convex octagon

Mathematics
1 answer:
muminat3 years ago
8 0


The sum of the interior angles of any polygon is always . . .

     (180 degrees ) times (2 less than the number of sides in the polygon) .

It doesn't matter whether the polygon is regular, haphazard, convex,
or all mangled and squashed etc.  The only thing that matters is
how many sides it has.

The octagon has 8 sides.  So the sum of interior angles is . . .

     (180 degrees) times (8 - 2) = (180 x 6) = <em>1,080 degrees</em>


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5xy + 4yz + 3zx for x = -1, y =-3, z = 4
neonofarm [45]

Answer:

-45

Step-by-step explanation:

5 *-1 *-3= 15

4 *-3 *4= -48

3 *4 *-1=-12

15 -48 -12= -45

8 0
3 years ago
Describe the relationship between n and 4 that will make the value of the expression 7 x n/4 greater than 7
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If n>4 then n/4>7
Hope I helped :)

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I need help on this question so if u actually can answer it correctly and show how you got it that would be helpful thx
Sedaia [141]

\rm \looparrowright -  \frac{1}{4} (8 - 4 + 20x)

Subtract the numbers

\rm \looparrowright -  \frac{1}{4} (4+ 20x)

Factor out 4 from the expression

\rm \looparrowright   - \frac{1}{ \cancel4}  \times  \cancel4(1 + 5x)

\rm \looparrowright   - (1 + 5x)

When there is a - in front of an expression in parentheses, change the sign of each term in the expression to -

\rm \looparrowright   - 1  -  5x

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6 0
2 years ago
Which of the following is an extraneous solution of (45-3x)^1/2=x-9?
Iteru [2.4K]

Answer:

C. x =3

Step-by-step explanation:

Extraneous solution is that root of a transformed equation that doesn't satisfy the equation in it's original form because it was excluded from the domain of the original equation.

Let's solve the equation first

\sqrt{45-3x} = x-9\\Taking\ square\ on\ both\ sides\\{(\sqrt{45-3x})}^2 = {(x-9)}^2\\45-3x = x^2-18x+81\\0 = x^2-18x+81-45+3x\\x^2-15x+36 = 0\\x^2-12x-3x+36 = 0\\x(x-12)-3(x-12) = 0\\(x-3)(x-12)\\x-3 = 0\\=> x =3\\x-12 = 0\\x = 12\\We\ will\ check\ the\ solutions\ one\ by\ one\\So,\\for\ x=3\\\sqrt{45-3(3)} = 3-9\\\sqrt{45-9} = -6\\\sqrt{36}= -6\\6\neq -6\\For x=12\\\sqrt{45-3(12)} = 12-9\\\sqrt{45-36} = 6\\\sqrt{36}= 6\\6=6

Hence, we can conclude that x=3 is an extraneous solution of the equation ..

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