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3 years ago

-8g-13=4384-x=27how do I solve these?

1 answer:

5 0

Solve for the variable

-8g-13=43 add 13 to both sides

-8g=56 divide both sides by -8

g=-7

84-x=27 subtract 84 from both sides

-x=-57 multiply both sides by -1

x=57

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What is the mean absolute deviation of 140,115,190,205,120,140,160,200,210,190

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3 years ago

What<br> is a common factor of 72 and 108

Tomtit [17]

Answer:

the step by step explanation gives you your answer

Step-by-step explanation:

The first step to find the gcf of 72 and 108 is to list the factors of each number. The factors of 72 are 1, 2, 3, 4, 6, 8, 9, 12, 18, 24, 36 and 72. The factors of 108 are 1, 2, 3, 4, 6, 9, 12, 18, 27, 36, 54 and 108.

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3 years ago

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I NEED HELP NOW!!!! I'LL MARK YOU BRAINLIEST IF YOU ANSWER!!!!!

rewona [7]

Answer:

0, 5, 7, 11, ...

Step-by-step explanation:

1^2 = 1; 1 - 1 = 0; 0 is divisible by 6

5^2 = 25; 25 - 1 = 24; 24 is divisible by 6

7^2 = 49; 49 - 1 = 48; 48 is divisible by 6

11^2 = 121; 121 - 1 = 120; 120 is divisible by 6

8 0

2 years ago

You want to rent an unfurnished one-bedroom apartment in Boston next year. The mean monthly rent for a random sample of 10 apart

Brilliant_brown [7]

Answer:

90% confidence interval: (2186.53;2881.47)

95% confidence interval: (2118.73;2949.27)

99% confidence interval: (1987.37;3080.63)

For the last part is not the best way say : "This interval describes the price of 95% of the rents of all the unfurnished one-bedroom apartments in the Boston area."

The best interpretation is this one: "We are 95% confident that the actual mean for the rents of unfurnished one-bedroom apartments in the Boston area is between (2118.73;2949.27)"

Step-by-step explanation:

1) Previous concepts

A confidence interval is "a range of values that’s likely to include a population value with a certain degree of confidence. It is often expressed a % whereby a population means lies between an upper and lower interval".

The margin of error is the range of values below and above the sample statistic in a confidence interval.

Normal distribution, is a "probability distribution that is symmetric about the mean, showing that data near the mean are more frequent in occurrence than data far from the mean".

$\bar X=2534$ represent the sample mean

$\mu$ population mean (variable of interest)

$\sigma=670$ represent the population standard deviation

n=10 represent the sample size

90% confidence interval

The confidence interval for the mean is given by the following formula:

$\bar X \pm z_{\alpha/2}\frac{\sigma}{\sqrt{n}}$ (1)

Since the Confidence is 0.90 or 90%, the value of $\alpha=0.1$ and $\alpha/2 =0.05$ , and we can use excel, a calculator or a tabel to find the critical value. The excel command would be: "=-NORM.INV(0.05,0,1)".And we see that $z_{\alpha/2}=1.64$

Now we have everything in order to replace into formula (1):

$2534-1.64\frac{670}{\sqrt{10}}=2186.53$

$2534+1.64\frac{670}{\sqrt{10}}=2881.47$

So on this case the 90% confidence interval would be given by (2186.53;2881.47)

95% confidence interval

The confidence interval for the mean is given by the following formula:

$\bar X \pm z_{\alpha/2}\frac{\sigma}{\sqrt{n}}$ (1)

Since the Confidence is 0.95 or 95%, the value of $\alpha=0.05$ and $\alpha/2 =0.025$ , and we can use excel, a calculator or a tabel to find the critical value. The excel command would be: "=-NORM.INV(0.025,0,1)".And we see that $z_{\alpha/2}=1.96$

Now we have everything in order to replace into formula (1):

$2534-1.96\frac{670}{\sqrt{10}}=2118.73$

$2534+1.96\frac{670}{\sqrt{10}}=2949.27$

So on this case the 95% confidence interval would be given by (2118.73;2949.27)

99% confidence interval

The confidence interval for the mean is given by the following formula:

$\bar X \pm z_{\alpha/2}\frac{\sigma}{\sqrt{n}}$ (1)

Since the Confidence is 0.99 or 99%, the value of $\alpha=0.01$ and $\alpha/2 =0.005$ , and we can use excel, a calculator or a tabel to find the critical value. The excel command would be: "=-NORM.INV(0.005,0,1)".And we see that $z_{\alpha/2}=2.58$

Now we have everything in order to replace into formula (1):

$2534-2.58\frac{670}{\sqrt{10}}=1987.37$

$2534+2.58\frac{670}{\sqrt{10}}=3080.63$

So on this case the 99% confidence interval would be given by (1987.37;3080.63)

For the last part is not the best way say : "This interval describes the price of 95% of the rents of all the unfurnished one-bedroom apartments in the Boston area."

The best interpretation is this one: "We are 95% confident that the actual mean for the rents of unfurnished one-bedroom apartments in the Boston area is between (2118.73;2949.27)"

7 0

3 years ago