-8g-13=43<br><br>84-x=27<br><br>how do I solve these?

It is claimed that automobiles are driven on average more than 20,000 kilometers per year. To test this claim, 100 randomly sele

kow [346]

Answer:

$t=\frac{23500-20000}{\frac{3900}{\sqrt{100}}}=8.974$

$p_v =P(t_{99}>8.974)=9.43x10^{-15}$

If we compare the p value and the significance level given for example $\alpha=0.05$ we see that $p_v$ so we can conclude that we to reject the null hypothesis, and the actual mean is significantly higher than 20000.

Step-by-step explanation:

1) Data given and notation

$\bar X=23500$ represent the sample mean

$s=3900$ represent the sample standard deviation

$n=100$ sample size

$\mu_o =2000$ represent the value that we want to test

$\alpha$ represent the significance level for the hypothesis test.

t would represent the statistic (variable of interest)

$p_v$ represent the p value for the test (variable of interest)

State the null and alternative hypotheses.

We need to conduct a hypothesis in order to determine if the true mean is higher than 20000, the system of hypothesis would be:

Null hypothesis: $\mu \leq 2000$

Alternative hypothesis: $\mu > 2000$

We don't know the population deviation, so for this case is better apply a t test to compare the actual mean to the reference value, and the statistic is given by:

$t=\frac{\bar X-\mu_o}{\frac{s}{\sqrt{n}}}$ (1)

t-test: "Is used to compare group means. Is one of the most common tests and is used to determine if the mean is (higher, less or not equal) to an specified value".

Calculate the statistic

We can replace in formula (1) the info given like this:

$t=\frac{23500-20000}{\frac{3900}{\sqrt{100}}}=8.974$

Calculate the P-value

First we need to calculate the degrees of freedom given by:

$df=n-1=100-1=99$

Since is a one-side upper test the p value would be:

$p_v =P(t_{99}>8.974)=9.43x10^{-15}$

Conclusion

If we compare the p value and the significance level given for example $\alpha=0.05$ we see that $p_v$ so we can conclude that we to reject the null hypothesis, and the actual mean is significantly higher than 20000.

8 0

3 years ago

Help please ASAPP pleaseee

vagabundo [1.1K]

I think it’s the first option

6 0

3 years ago

Please answer this correctly

Hoochie [10]

Answer:

3:48 P.M

because you add all the number making sure it's not greater than 60 and carry over to the next hour if it is

3 0

3 years ago

Read 2 more answers

To test the belief that sons are taller than their fathers, a student randomly selects 13 fathers who have adult male children.

KATRIN_1 [288]

Answer:

1) B. The differences are normally distributed or the sample size is large

C. The sample size mus be large

E. The sampling method results in an independent sample

2) The null hypothesis H₀: $\bar x_1$ = $\bar x_2$

The alternative hypothesis Hₐ: $\bar x_1$ < $\bar x_2$

Test statistic, t = -0.00693

p- value = 0.498

Do not reject Upper H₀ because, the P-value is greater than the level of significance. There is sufficient evidence to conclude that sons are the same height as their fathers at 0.10 level of significance

Step-by-step explanation:

1) B. The differences are normally distributed or the sample size is large

C. The sample size mus be large

E. The sampling method results in an independent sample

2) The null hypothesis H₀: $\bar x_1$ = $\bar x_2$

The alternative hypothesis Hₐ: $\bar x_1$ < $\bar x_2$

The test statistic for t test is;

$t=\dfrac{(\bar{x}_1-\bar{x}_2)}{\sqrt{\dfrac{s_{1}^{2} }{n_{1}}-\dfrac{s _{2}^{2}}{n_{2}}}}$

The mean

Height of Father, h₁, Height of Son h₂

72.4, 77.5

70.6, 74.1

73.1, 75.6

69.9, 71.7

69.4, 70.5

69.4, 69.9

68.1, 68.2

68.9, 68.2

70.5, 69.3

69.4, 67.7

69.5, 67

67.2, 63.7

70.4, 65.5

$\bar x_1$ = 69.6

s₁ = 1.58

$\bar x_2$ = 69.9

s₂ = 3.97

n₁ = 13

n₂ = 13

$t=\dfrac{(69.908-69.915)}{\sqrt{\dfrac{3.97^{2}}{13}-\dfrac{1.58^{2} }{13}}}$

(We reversed the values in the square root of the denominator therefore, the sign reversal)

t = -0.00693

p- value = 0.498 by graphing calculator function

P-value > α Therefore, we do not reject the null hypothesis

Do not reject Upper H₀ because, the P-value is greater than the level of significance. There is sufficient evidence to conclude that sons are the same height as their fathers at 0.10 lvel of significance

8 0

4 years ago

A turtle and a snail are 300 feet apart when they start moving towards each other. The turtle is moving at a speed of 5 feet per

givi [52]

Answer:

It Is 60

Step-by-step explanation:

300/5=60x1=60

3 0

3 years ago

Read 2 more answers

-8g-13=4384-x=27how do I solve these?