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tino4ka555 [31]
3 years ago
9

In which quadrant does the terminal side of a 135° angle in standard position lie?

Mathematics
2 answers:
sveta [45]3 years ago
7 0
First quadrant: 0° - 90°
Second quadrant: 90° - 180°
Third quadrant: 180° - 270°
Fourth quadrant: 270° - 360°

So, your answer: second quadrant.

Look at the picture.

dolphi86 [110]3 years ago
6 0
Solutions 

The terminal side of an angle in standard position is a ray that has been rotated from the positive (x) <span>axis. 

</span>If the angle measure is positive <span>the rotation is counterclockwise 

</span>If the angle measure is negative the <span>rotation is counterclockwise.  
</span>

The angle measure is positive, so the rotation is 135° is <span>counterclockwise. 
</span>
Rotate the ray 135° counterclockwise. This rotation puts the terminal side in Quadrant <span>II.</span>
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0.26/100= 26%

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The position function for a free-falling object is s(t) = -16t^2 + vt +5. A ball is thrown upward from the top of a 400-foot bui
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6.21 seconds

Step-by-step explanation:

The position function of a free-falling object is,

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v_0 = initial velocity of the object,

Here,

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v_0=35\text{ feet per sec}

Hence, the height of the ball after t seconds,

s(t)=-16t^2+35t+400

When s(t) = 0,

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Hence, after 6.21 seconds the ball will reach the ground.

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