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Ugo [173]
3 years ago
12

If p(x) = 2x2 – 4x and q(x) = x – 3, what is mc007-1.jpg? 2x2 – 4x + 12 2x2 – 16x + 18 2x2 – 16x + 30 2x2 – 16x + 15

Mathematics
2 answers:
adelina 88 [10]3 years ago
7 0

Answer:

C ) 2x2 – 16x + 30

Step-by-step explanation:


Rainbow [258]3 years ago
3 0
P(x) = 2x² - 4xq(x) = x - 3
To find the answer, we plug q(x) into p(x):
p(q(x)) = 2(x - 3)² - 4(x - 3)p(q(x)) = 2(x² - 6x + 9) - 4x + 12p(q(x)) = 2x² - 12x + 18 - 4x + 12p(q(x)) = 2x² - 16x + 30
The third option is correct.

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Which of the following rational functions is graphed below?
Cerrena [4.2K]

Answer:

option B

Step-by-step explanation:

We can see in the graph that the function has two values of x where the value of y goes to infinity: x = -6 and x = 6.

These points where the value of the function goes to infinity usually are roots of the polynomial in the denominator of a fraction (when the values of x tend to these values, the denominator of the fraction tends to 0, so we have a discontinuity in the function).

So the option that represents a function that have these points in x = -6 and x = 6 is the function in option B.

The other options show functions that have only one point that goes to infinity.

7 0
4 years ago
The Wall Street Journal Corporate Perceptions Study 2011 surveyed readers and asked how each rated the Quality of Management and
kykrilka [37]

Answer:

The calculated χ² =  <u>17.0281</u>    falls in the critical region χ² ≥  9.49  so we reject the null hypothesis that  the quality of management and the reputation of the company are independent and conclude quality of management and the reputation of the company are dependent

The p-value is 0 .001909. The result is significant at p < 0.05

Part b:

40 > 8.5

35> 7.5

25> 4

Step-by-step explanation:

1) Let the null and alternative hypothesis as

H0: the quality of management and the reputation of the company are independent

against the claim

Ha: the quality of management and the reputation of the company are dependent

2) The significance level alpha is set at 0.05

3) The test statistic under H0 is

χ²= ∑ (o - e)²/ e where O is the observed and e is the expected frequency

which has an approximate chi square distribution with ( 3-1) (3-1)=  4 d.f

4) Computations:

Under H0 ,

Observed       Expected E              χ²= ∑(O-e)²/e

40                      35.00                          0.71

25                      24.50                         0.01

5                         10.50                         2.88  

35                      40.00                         0.62

35                      28.0                          1.75

10                       12.00                           0.33  

25                      25.00                             0.00

10                        17.50                              3.21

<u>15                       7.50                                 7.50  </u>

<u>∑                                                               17.0281</u>

     

     

Column Totals 100 70 30   200  (Grand Total)

5) The critical region is χ² ≥ χ² (0.05)2 = 9.49

6) Conclusion:

The calculated χ² =  <u>17.0281</u>    falls in the critical region χ² ≥  9.49  so we reject the null hypothesis that  the quality of management and the reputation of the company are independent and conclude quality of management and the reputation of the company are dependent.

7) The p-value is 0 .001909. The result is significant at p < 0.05

The p- values tells that the variables are dependent.

Part b:

If we take the excellent row total = 70 and compare it with the excellent column total= 100

If we take the good row total = 70 and compare it with the good column total= 80

If we take the fair row total = 50 and compare it with the fair column total= 30

The two attributes are said to be associated if

Thus we see that ( where (A)(B) are row and columns totals and AB are the cell contents)

AB> (A)(B)/N  

40 > 1700/200

40 > 8.5

35> 1500/200

35> 7.5

25> 800/200

25> 4

and so on.

Hence they are positively associated

8 0
3 years ago
Julie runs a catering business. Last year she catered 212 dinner events and 148 lunch events. Which proportion could be used to
siniylev [52]

Answer:

Step-by-step explanation:

the percent = # of dinner events/(total # of events)

= 212/(212 + 148)

= 212/360

= 0.5889

= 58.89%

3 0
3 years ago
Read 2 more answers
Evaluate the expression for the given values.<br> 12x+5y/3z, where x + 1/2, y = 6 and z = 3
Semmy [17]

Answer:

4

Step-by-step explanation:

Substitute: \frac{\frac{12}{2} +5*6}{3*3}

Cross out the common factor: \frac{6+5*6}{3*3}

Calculate the product or quotient: \frac{6 +30}{3*3}

Calculate the product or quotient: \frac{6+30}{9}

Calculate the sum or difference: \frac{36}{9}

Cross out the common factor: 4

Answer: 4

6 0
2 years ago
Read 2 more answers
The manager of a shopping mall distributed a customer-satisfaction survey by handing it to people as they came through one of th
Tresset [83]

Answer:

The correct option is D.  No, because a random sample from all customers of the shopping mall was not selected

Step-by-step explanation:

In statistics, Bias can be described as a term which depicts error if a sample is not taken evenly or it depicts errors taken from an unjust sampling.

In statistics, sampling bias means the errors which occur if one part of the population is favoured more then the rest of the populations. In this kind of bias, the individuals for experimentation are not chosen randomly.

As the customer satisfaction survey was distributed in only one of the gates hence, it does not give a generalized result and the result is biased.

6 0
4 years ago
Read 2 more answers
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