part A)



part B)
well, we know y = -2x+8.... so.. what's the runner's velocity after 5hours? well, x = 5, thus y = -2(5) +8 ---> y = -2
to graph it, well, is a LINEar equation, meaning the graph is a LINE, and to graph a line, all you need is two points, and by now, you have more than two.. so graph it away.
Answer:
4 1/6
Step-by-step explanation:
4 x 6 = 24
1/6 x 6 = 6/6 = 1
24 + 1 = 25 :)
Answer:
(a)
and 
(b) The sample variance is
and the sample standard deviation is 
Step-by-step explanation:
(a)
The sum of these 17 sample observations is

and the sum of their squares is

(b)
The sample variance, denoted by
, is given by

where 
Applying the above formula we get that


The sample standard deviation, denoted by <em>s</em>, is the (positive) square root of the variance:

Applying the above formula we get that

Answer:

Step-by-step explanation:
We need to find the probability that the mechanic will service or more cars.
It's a simpler one given that we have the probabilities of servicing 4 or less cars.
P(at least 5 cars) is given by subtracting the probabilities of servicing both 3 and 4 cars.
