Answer:
sorry but i'm in class right now
Step-by-step explanation:
![f(x) = \sqrt[3]{x - 3}](https://tex.z-dn.net/?f=f%28x%29%20%3D%20%5Csqrt%5B3%5D%7Bx%20-%203%7D)
The domain of a function are the values of 
that you can plug into the function 
.
Values inside of a root must be non-negative, which means that 
must be greater than or equal to zero. We can set up an equation to find the domain:
With this, we know the domain of the function is 
.
The range of a function are the values that can have. Since the equation is a cube root, the value will always be non-negative, meaning the range of the function is 
.
Idk for sure but im thinking 8/12? idk sorry
Why are you taking a map test in january
Answer:
Step-by-step explanation:
I assume that you mean
sec(x)-tan(x) = 1 / ( sec(x) + tan(x) ) , right ?
then this is equivalent to
[ sec(x) - tan(x) ] x [ sec(x) + tan(x) ] = 1
let s evaluate it, we got
sec2(x) - sec(x)tan(x) + - sec(x)tan(x) - tan2(x) = sec2(x) - tan2(x)
= (1 - sin2(x) ) / cos2(x) = cos2(x) / cos2(x) = 1
as cos2(x) + sin2(x) = 1
