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Alchen [17]
3 years ago
5

How do you do this???

Mathematics
1 answer:
densk [106]3 years ago
7 0

Answer:

Step-by-step explanation:

∠ E  =∠ B    { corresponding part of congruence triangle are equal}

2x + 4 = 40

2x = 40 - 4

2x = 36

x = 36/2

x = 18

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Last one, use trigonometry to help you solve for y given that one side is 4 and there is an angle of 50 degrees.
Ostrovityanka [42]

Answer:

y = 6.22

You can solve this in two ways.

1.) Use SOH CAH TOA:

I typically start off by labeling the sides of the triangle with H (hypotenuse), O (opposite), and A (adjacent). Because I need to figure out what y is when given an angle and 4, I will use CAH, or cosine.

\cos(angle)  =  \frac{adjacent}{hypotenuse}

\cos(50)  =  \frac{4}{y}

\cos(50)  \times y = 4

y =  \frac{4}{ \cos(50) }

y = 6.22

2.) Use Law of Sines:

Solve for the last angle inside the triangle first.

180 - (50 + 90) = 40

Then use the angle you found (40°) in the equation.

\frac{4}{ \sin(40) }  =  \frac{y}{ \sin(90) }

\frac{4}{ \sin(40) }  \times  \sin(90)  = y

y = 6.22

3 0
3 years ago
Find the term that must be added to the equation x2 6x=1 to make it into a perfect square.
andrezito [222]

The value added to the equation $x^2-6x=1 exists $x^2-6x+9=10.

<h3>What is a perfect square?</h3>

A perfect square exists as a number that can be described as the product of an integer by itself or as the second exponent of an integer.

The perfect square trinomial exists

(a ± b)^2 = a ^2 ± 2ab + b ^2

$x^2-6x=1

x^2-2*3x=1

then $2ab = 2 * 3*x = 2 * x *3

The value of a = x and b = 3

$b^2=3^2=9

$x^2-6x+9=1+9

$x^2-6x+9=10

The value added to the equation $x^2-6x=1 exists $x^2-6x+9=10.

To learn more about perfect square refer to: brainly.com/question/6946048

#SPJ4

3 0
2 years ago
How to solve number 4
s2008m [1.1K]
Find the first semicircle area
Area semicircle can be determined by dividing the full area of circle by 2.
The first semicircle radius is 5 cm
semicircle area = 1/2 circle area
semicircle area = 1/2 × π × r²
semicircle area = 1/2 × 3.14 × 5²
semicircle area = 1/2 × 3.14 × 25
semicircle area = 39.25 cm²

Find the second semicircle area
Because the dimension of the second semicircle is congruent to the first semicircle, they have similar area measurement, 39.25 cm².

Find the quarter circle area
The area of quarter circle can be determined by dividing the full area of a circle by 4.
q circle = 1/4 × area of circle
q circle = 1/4 × π × r²
q circle = 1/4 × 3.14 × 10²
q circle = 1/4 × 314
q circle = 78.5 cm²

To find the entire area, add the area above together
area = first semicircle + second semicircle + q circle
area = 39.25 + 39.25 + 78.5
area = 157

The area of shaded region is 157 cm²
4 0
3 years ago
Triangle ABC is shown with line DE running horizontally through the center of the figure.
vichka [17]

Answer:

If triangle ABC is dilated by a scale factor of three about the center of the triangle, dilated line D'E' will be parallel to the original line. As the triangle is dilated, the line will move up. This is because the center of the triangle does not lie on DE.

3 0
3 years ago
What geometric term describes a corner of the living room
Kay [80]
The corner of a living room is called the Vertex

5 0
3 years ago
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