The first term, a, is 2. The common ratio, r, is 4. Thus,
a_(n+1) = 2(4)^(n).
Check: What's the first term? Let n=1. Then we get 2(4)^1, or 8. Is that correct? No.
Try this instead:
a_(n) = a_0*4^(n-1). Is this correct? Seeking the first term (n=1), does this formula produce 2? 2*4^0 = 2*1 = 2. YES.
The desired explicit formula is a_(n) = a_0*4^(n-1), where n begins at 1.
I can’t see your question I wish I could help you
X values are increasing by 2
y values are increasing by 4
Mark is correct
2/3 think of this as a pie right divided into 3 area but only 2 people eat from it 1 left but how would i complete it if its not done well i need to complete the "pie"
by adding an exponent into the mesure and cacultating a mass of a=mx+b
now you divide and get 0.75
so you will fill in .25 more to get the full measurement by eating 1 more pie:
