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Nata [24]
3 years ago
5

Calculate the quotient.

Mathematics
1 answer:
lidiya [134]3 years ago
5 0

A) 3/4 ÷ 5 1/5.

Answer:

\frac{15}{104}

B) 3/7 ÷ 2 1/2.

Answer:

\frac{6}{35}

C) 5/8 ÷ 6 5/6.

Answer:

\frac{15}{164}

D) 8 3/10 ÷ 5/8.

Answer:

13 \frac{7}{25}

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Suppose that a sample of size 100 is to be drawn from a population with standard deviation 10.
larisa86 [58]

Answer:

a) 68% probability that the sample mean will be within 1 of the value of μ.

b)

1)

Approximately 95% of the time, x will be within 2 of μ.

2)

Approximately 0.3% of the time, x will be farther than 3 from μ.

The last:

n = 40

n = 65

n = 130

n = 520

Step-by-step explanation:

To solve this problem, it is important to know two concepts: The Empirical Rule and the Central Limit Theorem.

Empirical Rule

The Empericial Rule states that, for a normally distributed random variable:

68% of the measures are within 1 standard deviation of the mean.

95% of the measuers are within 2 standard deviations of the mean.

99.7% of the measures are within 3 standard deviations of the mean.

Central Limit Theorem

The Central Limit Theorem estabilishes that, for a random variable X, with mean \mu and standard deviation \sigma, a large sample size, of at least 30, can be approximated to a normal distribution with mean \mu and standard deviation \frac{\sigma}{\sqrt{n}}.

Suppose that a sample of size 100 is to be drawn from a population with standard deviation 10.

So \sigma = 10, n = 100, s = \frac{10}{\sqrt{100}} = 1

(a) What is the probability that the sample mean will be within 1 of the value of μ?

Within 1 is within one standard deviation of the mean \mu.

So there is a 68% probability that the sample mean will be within 1 of the value of μ.

(b) For this example (n = 100, σ = 10), complete each of the following statements by computing the appropriate value. (Round the answers to the nearest whole number.)

(1) Approximately 95% of the time, x will be within___ of μ.

By the empirical rule, 95% of the measures are within 2 standard deviations of the mean. In our sample, the standard deviation is 1.

So

Approximately 95% of the time, x will be within 2 of μ.

(2) Approximately 0.3% of the time, x will be farther than___ from μ.

By the empirical rule, 99.7% of the measures are within 3 standard deviations of the mean. In the other 0.3% of the time, the measures are farther than 3 standard deviations of the mean. In our sample, the standard deviation is 1.

So:

Approximately 0.3% of the time, x will be farther than 3 from μ.

A random sample is selected from a population with mean μ = 100 and standard deviation σ = 10. For which of the sample sizes would it be reasonable to think that the xsampling distribution is approximately normal in shape? (Select all that apply.)

As we saw above, in the central Limit theorem, we should use a sample size of at least 30. So

n = 40

n = 65

n = 130

n = 520

7 0
3 years ago
PLEASE HELP ME IM IN A TEST, THIS IS A 6TH GRADER QUESTION ILL GIVE U THANKS
jeyben [28]

Answer:C

Step-by-step explanation:

A.Is correct since 40 plus 8.032 is 48.031 (Check Your selves)

B.Is correct since 48 ones = 48 and 31 thousandths =0.31

C.Is Wrong since 48(Well is correct )plus 0.31 not 0.031,not 31 thousandths.

D.Correct since 40 plus 8=48 and 0.03+0.0001 is 0.031.

Hope this helped!

If you are reading this hope you have a wonderful day and may your dreams come true!

Tell me if its wrong

lfu29

3 0
3 years ago
Read 2 more answers
Evaluate 1/4 plus 5/8. please show work
adelina 88 [10]

Answer:

7/8.

Step-by-step explanation:

The LCD of 4 and 8 is 8.

So we convert: 1/4 = 2/8.

2/8 + 5/8 = 7/8  (answer).

6 0
4 years ago
What is the whole number portion of the decimal? (5.024) What is the decimal portion of the decimal? (176.261)
oksian1 [2.3K]

The whole number portion is always the number to the left of the decimal. In this case it is 5. You have to be careful what you say if you are working in scientific notation.

For your second question 0.261 is the decimal portion. If the only part present was 0.261,  then 0 is the whole number portion, believe it or not. Nice question. You can learn a lot from it.

5 0
3 years ago
Can someone help me with this math problem ?? Pls it’s for my final !
Airida [17]

Answer:

221.87 feet

Step-by-step explanation:

Given that,

A 525 ft cable runs from the top of an antenna to the ground.

The angle of elevation made by the ground to the top of an antena 25°

We need to find the height of the antenna.

Using trigonometry,

Hypotenuse, H = 525 ft

θ = 25°

So,

\sin\theta=\dfrac{P}{H}\\\\P=H\sin\theta\\\\P=525\times \sin(25)\\\\P=221.87\ ft

So, the height of the antenna is equal to 221.87 feet.

4 0
3 years ago
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