Choose the correct description of the graph of the compound inequality shown below;

No links, ty <3

levacccp [35]

Answer:

sAy yOu aRe mY bAkA

Step-by-step explanation:

ty for the points <3

4 0

3 years ago

Please helppp answer quick

hoa [83]

Answer is C:1/3

21 total
7/21=1/3

4 0

3 years ago

1/2x + 4=9 What does x equal?

Ludmilka [50]

Answer:

x=10

Step-by-step explanation:

1/2x+4=9

subtract 4 from both sides

1/2x=5

multiply both sides by 2 to get x by itself

x=10

5 0

3 years ago

Read 2 more answers

A baseball team consists of 2 stars, 13 starters, and 10 substitutes. For tax purposes, the team owner must value the players. T

inessss [21]

Answer:

The total value of the team=$8.2 million

Step-by-step explanation:

Step 1

Determine the total value of the team as follows;

V=(S×s)+(T×t)+(B×b)

where;

V=total value of the team

S=total value per star player

s=number of stars in the team

T=total value per starter

t=number of starters in the team

B=total value per substitute

b=number of substitutes in the team

In our case;

S=1 million per year

s=2 stars

T=400,000

t=13

B=100,000

b=10

replacing;

V=(1,000,000×2)+(400,000×13)+(100,000×10)

V=(2,000,000+5,200,000+1,000,000)

V=8,200,000=8.2 million

The total value of the team=$8.2 million

4 0

3 years ago

Basic Computation: Testing M1 2 M2 A random sample of 49 measurements from a population with population standard deviation 3 had

Elenna [48]

Answer:

The sample statistics follows a standard normal distribution since the sample size are large enough.

Step-by-step explanation:

Given that:

First population:

Sample size $n_1$ = 49

Population standard deviation $\sigma_1$ = 3

Sample mean $\overline x _1$ = 10

Second population:

Sample size $n_2$ = 64

Population standard deviation $\sigma_2$ = 4

Sample mean $\overline x_2$ = 12

The sample statistics follows a standard normal distribution since the sample size are large enough.

The null and alternative hypotheses can be computed as:

$\mathbf{H_o:\mu_1=\mu_2}$

$\mathbf{H_1:\mu_1\ne\mu_2}$

Level of significance = 0.01

Using the Z-test statistics;

$Z = \dfrac{\overline x_1 - \overline x_2}{\sqrt{\dfrac{\sigma_1^2}{n_1} + \dfrac{\sigma_2^2}{n_2}}}$

$Z = \dfrac{10- 12}{\sqrt{\dfrac{3^2}{49} + \dfrac{4^2}{64}}}$

$Z = \dfrac{-2}{\sqrt{\dfrac{9}{49} + \dfrac{16}{64}}}$

$Z = \dfrac{-2}{\sqrt{0.18367 +0.25}}$

$Z = \dfrac{-2}{\sqrt{0.43367}}$

$Z = \dfrac{-2}{0.658536}$

Z = - 3.037

Z $\simeq$ - 3.04

The P-value = 2P (z < -3.04)

From the z tables

= 2 × (0.00118)

= 0.00236

Thus, since P-value is less than the level of significance, we fail to reject the null hypotheses $H_o$

5 0

3 years ago