a. Jada got the measurement 16m.
b. The measured depth differ 0.2m from the actual depth.
c. There is a 12.66% error in calculation.
Step-by-step explanation:
Given,
The depth of lake = 15.8 m
a. Jada accurately measured the depth of the lake to the nearest meter. What measurement did Jada get
When a digit after the decimal point is 5 or more than that, the number before decimal is rounded to the next number.
Therefore,
15.8 rounded to nearest number is 16.
The depth of lake measured by Jada = 16 m
Jada got the measurement 16m.
b. By how many meters does the measured depth differ from the actual depth?
Difference = Approx - Exact
Difference = 16 - 15.8 = 0.2m
The measured depth differ 0.2m from the actual depth.
c. Express the measurement error ad a percentage of the actual depth.
Percent error = 
Percent error = 
Percent error = 12.66%
There is a 12.66% error in calculation.
Keywords: percent, error
Learn more about percent at:
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If by markup you mean discount then.....
1.5*0.07 = $0.105
That must be a very good pen ;D
Answer:
4 and 1/3
Step-by-step explanation:
3 can go into 13 4 times with one left over
my rank is expert
hope this helps
Answer:
The principal investment required to get a total amount of $ 1,000,000.00 from compound interest at a rate of 6% per year compounded 12 times per year over 45 years is $ 67,659.17.
Step-by-step explanation:
Given
- Accrued Amount A = $1000000
- Interest rate r = 6% = 0.06
- Compounded monthly n = 12
To determine:
Using the formula


substituting A = 1000000, r = 0.06, t = 45, and n = 12


$
Therefore, the principal investment required to get a total amount of $ 1,000,000.00 from compound interest at a rate of 6% per year compounded 12 times per year over 45 years is $ 67,659.17.