All categories

3 years ago

I need help with this ASAP

Mathematics

1 answer:

Nitella [24]3 years ago

7 0

Answer:

The answer is A

Step-by-step explanation:

Hope this helps!

You might be interested in

Find the value of x. Round to the nearest tenth

Inessa05 [86]

the answer should be 12. but I'm only 80% sure sooo...

5 0

3 years ago

PLEASE HELP ASAP 25 PTS + BRAINLIEST FOR RIGHT/BEST ANSWER

sergejj [24]

8y = 4x -16

-x = -2y -4

Multiply all terms in the second equation by -1:

-x = -2y -4 x -1 = x = 2y +4

Now replace x in the first equation with this.

8y = 4(2y+4)

Simplify:

8y = 8y +16

Because there is an 8y on both sides of the equation, it cannot be solved.

The answer is no solution.

6 0

3 years ago

5 less than the product of -2 and a number is no more than 15.

vladimir1956 [14]

Answer:

-2x - 5 (lesser than or equal to) 15

6 0

2 years ago

Suppose a 90% confidence interval for the mean salary of college graduates in a town in Mississippi is given by [$38,737, $50,46

JulsSmile [24]

Answer:

a. The point estimate was of $44,600.

b. The sample size was of 16.

Step-by-step explanation:

Confidence interval concepts:

A confidence interval has two bounds, a lower bound and an upper bound.

A confidence interval is symmetric, which means that the point estimate used is the mid point between these two bounds, that is, the mean of the two bounds.

The margin of error is the difference between the two bounds, divided by 2.

a. What is the point estimate of the mean salary for all college graduates in this town?

Mean of the bounds, so:

(38737+50463)/2 = 44600.

The point estimate was of $44,600.

b. Determine the sample size used for the analysis.

First we need to find the margin of error, so:

$M = \frac{50463-38737}{2} = 5863$

Relating the margin of error with the sample size:

We have that to find our $\alpha$ level, that is the subtraction of 1 by the confidence interval divided by 2. So:

$\alpha = \frac{1 - 0.9}{2} = 0.05$

Now, we have to find z in the Z-table as such z has a p-value of $1 - \alpha$ .

That is z with a pvalue of $1 - 0.05 = 0.95$ , so Z = 1.64.

Now, find the margin of error M as such

$M = z\frac{\sigma}{\sqrt{n}}$

In which $\sigma$ is the standard deviation of the population and n is the size of the sample.

For this problem, we have that $\sigma = 14300, M = 5863$ . So

$M = z\frac{\sigma}{\sqrt{n}}$

$5863 = 1.645\frac{14300}{\sqrt{n}}$

$5863\sqrt{n} = 1.645*14300$

$\sqrt{n} = \frac{1.645*14300}{5863}$

$(\sqrt{n})^2 = (\frac{1.645*14300}{5863})^2$

$n = 16$

The sample size was of 16.

7 0

3 years ago

James usually drinks 38 ounces of water per day. He read that he should drink 64 ounces of water per day. If he starts drinking

vova2212 [387]

Answer at very bottom of picture above

if explanation need comment

7 0

3 years ago