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serious [3.7K]
3 years ago
10

Please show work! 4k+15m+2m−5k Thanks so much!

Mathematics
1 answer:
tatyana61 [14]3 years ago
7 0
Combine like term ,

4K - 5k = -1k

15m + 2m = 17 m

Put it all together and you get...

17m - 1k
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Elk middle school has 264 students. There are 84 students in the eighth grade. There are 22 fewer seventh-grade students than si
Vinvika [58]

Answer:

There were 84 students in 6th grade, 68 in 7th grade, and 90 in 8th grade.

Step-by-step explanation:

Given that Elk middle school has 264 students, and there are 84 students in the eighth grade, and there are 22 fewer seventh-grade students than sixth-grade students, to determine how many students there are in each grade, the following calculation must be performed:

(264 - 84) / 2) - 22 = X

(180/2) - 22 = X

90 - 22 = X

68 = X

6th grade = 84

7th grade = 68

8th grade = 90

Therefore, there were 84 students in 6th grade, 68 in 7th grade, and 90 in 8th grade.

3 0
3 years ago
I’m not sure which answer it is !??
Shkiper50 [21]

Answer:

Its A or B if not then sorry

Step-by-step explanation:

5 0
3 years ago
(6+2i)÷3i solve this problem <br>​
Vsevolod [243]
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5 0
3 years ago
The triangles are similar.<br> What is the value of x?<br> Enter your answer in the box.<br><br> X=
Aleks04 [339]

Answer:

x=16

Step-by-step explanation:

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4 0
3 years ago
A blimp can be seen flying at an altitude of 5500 feet above a motor speedway during a race. The slanted distance directly to th
Vladimir [108]

Answer:

The expression of h as function of x is   h = \sqrt{(d + 5500) (d - 5500)}

Step-by-step explanation:

Given as :

The distance of blimp  (AB) = 5500 feet

The slanted distance to the pagoda (BC) = d feet

The horizontal distance (AC) = h

Let the angle made between slanted distance and horizontal distance be Ф

So , cos Ф = \frac{AC}{BC} = \frac{h}{d}

And sin Ф =  \frac{AB}{BC} = \frac{5500}{d}

∵, cos²Ф = 1 - sin²Ф

So, (\frac{h}{d})^{2} = 1 - (\frac{5500}{d})^{2}

Or, (\frac{h}{d})^{2} = (\frac{d^{2}- 5500^{2}}{d^{2}})

Or,                                     h² = d² - 5500²

∴                                        h = \sqrt{d^{2}- 5500^{2}}

Or,                                     h = \sqrt{(d + 5500) (d - 5500)}

Hence The expression of h as function of x is   h = \sqrt{(d + 5500) (d - 5500)}     Answer

3 0
3 years ago
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