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dimaraw [331]
4 years ago
13

A reversible heat pump and a Carnot heat pump operate between the same two thermal reservoirs. Which heat pump has higher COP?

Engineering
1 answer:
jonny [76]4 years ago
4 0

Answer:

Both heat pump has same COP

Explanation:

Given that a reversible heat pump and a Carnot heat pump which is operating between the same temperature limits will have the same COP because the temperature limits are same, that is the source temperature and the sink temperature. Also because we know that a Carnot cycle is a totally reversible cycle. Therefore for a perfectly reversible Carnot cycle, the COP will be same for a reversible heat pump and a Carnot heat pump operating between two same thermal reservoirs.

Thus, both heat pump will have same COP.

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What happens when force is placed on a square/rectangle?
mart [117]

im not sure i need to see a photo and also is this science

7 0
3 years ago
Read 2 more answers
2 samples of water of equal volume are put into dishes and kept at room temp for several days. the water in the first dish is co
Over [174]

Answer:

Vaporization is the process by which a substance changes from its solid or liquid state to a gaseous state.

Since both liquids are of the same volume and are placed under the same temperature condition, for them to not to vaporize at the same time, they must have been in different containers.

For vaporization to take place, the volume of liquid, amount of air exposure and area of the surface must be considered.

Maybe the first liquid was in a dish which has a large opening, thereby exposing a large amount which can make water to evaporate faster, whereas the second liquid was somehow enclosed (in a deeper dish).

5 0
3 years ago
Suppose there are 93 packets entering a queue at the same time. Each packet is of size 4 MiB. The link transmission rate is 1.4
Ghella [55]

Answer:

0.19s

Explanation:

Queueing delay is the time a job waits in a queue before it can be executed. it is the difference in time betwen when the packet data reaches it destination and the time when it was executed.

Queueing delay =(N-1) L /2R

where N = no of packet =93

L = size of packet = 4MB

R = bandwidth = 1.4Gbps = 1×10⁹ bps

4 MB = 4194304 Bytes

(93 - 1)4194304 / 2× 10⁹

queueing delay =192937984 ×10⁻⁹

=0.19s

5 0
3 years ago
A good visual lead is .... seconds from the front of the vehicle, focusing in the center of the path of travel. Searching 20 to
Tomtit [17]

A good visual lead is 20-30 seconds from the front of the vehicle, focusing in the center of the path of travel. Searching 20 to 30 seconds ahead, gives you time to assess within the next ..12-15 seconds, actions you may need to take to control an approaching risk.

Discussion:

Keeping eye focus centered in a path of travel at an interval of 20 to 30 seconds away from the vehicle is critical to gaining enough info. as possible in the driving scene. Good targeting sets up good sight lines for referencing and good peripheral fields for observing changes.

  • It is important to look ahead 12-15 seconds into your target area as one drives. Compromise. space by giving as much space to the greater of two hazards.

Read more on driving visual leads:

brainly.com/question/7067386

3 0
3 years ago
A 12-ft high retaining wall has backfill of granular soil with an internal angle of friction of 30 and unit weight of 125 pef. W
irakobra [83]

Answer:

P_p = 27000 psf

Explanation:

given,

height of the retaining wall = h = 12 ft

internal angle of friction (∅)= 30°

unit weight = 125 pcf

Rankine passive earth pressure = ?

k_p is the coefficient of passive earth pressure

k_p = \dfrac{1 + sin\phi}{1 - sin\phi}

k_p = \dfrac{1 + sin30^0}{1 - sin30^0}

k_p = 3

Passive earth pressure

P_p = \dfrac{1}{2}k_p \gamma H^2

P_p = \dfrac{1}{2}\times 3\times 125 \times 12^2

      P_p = 27000 psf

Rankine passive earth pressure on the wall is equal to P_p = 27000 psf

7 0
3 years ago
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