The diameter of an automobile tire is closest to
1 answer:
Answer:
(1) 10^−2 m
Explanation:
The diameter of the tire of an automobile is generally expressed in centimetres; we can say that the diameter of a tire is generally about
d = 20 cm (20 centimetres)
Now we have to verify which option is closest to this value. To do that, we have to keep in mind the equivalence between metres and centimetres; in fact, we have:
This means that we can rewrite the diameter of the tire of a car as
By comparing it with the given options, we see that the closest option is
(1) 10^−2 m
which is therefore the correct answer.
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Answer and Explanation:
Here's the answer!
<u>Complete Question:</u>
Devon has several toy car bodies and motors. The motors have the same mass, but they provide different amounts of force, as shown in this table.
The bodies have the masses shown in this table (refer attached figure).
Which motor and body should Devon use to build the car with the greatest acceleration?
motor 1, with body 1
motor 1, with body 2
motor 2, with body 1
motor 2, with body 2
<u>Answer:</u>
Devon should build the car with motor 2 and body 1 for having the greatest acceleration.
<u>Explanation:</u>
As per Newton's second law of motion, the acceleration of any object is directly proportional to the force on the object and inversely proportional to the mass of the object.
It can be seen that motor 2 has greater force than the force provided by motor 1. Similarly, the mass of body 1 is found to be lesser compared to mass of body 2. So,
It gives, the system with motor 2 and body 1 the maximum acceleration. So the car should be built with motor 2 and body 1.
Answer:
Fe= 2579.68 P
α= 24.8°
Explanation:
Look at the attached graphic
we take the forces acting on the x-y plane and applied at the origin of coordinates
FX = 1260 P , horizontal (-x)
FY = 1530 P , forming 45° with positive x axis
x-y components FY
FYx= - 1530*cos(45)° = - 1081.87 P
FYy= - 1530*sin(45)° = - 1081.87 P
Calculation of the components of net force (Fn)
Fnx= FX + FYx
Fnx= -1260 P -1081.87 P
Fnx= -2341.87 P
Fny=FYy
Fny= -1081.87 P
Calculation of the components of equilibrant force (Fe)
the x-y components of the equilibrant force are equal in magnitude but in the opposite direction to the net force components:
Fnx= -2341.87 P, then, Fex= +2341.87 P
Fny= -1081.87 P P, then, Fex= +1081.87 P
Magnitude of the equilibrant (Fe)
Fe= 2579.68 P
Calculation of the direction of equilibrant force (α)
α= 24.8°
Look at the attached graphic
