Answer:
182.9 Volts
Explanation:
R = resistance of the resistor = 50 Ω
C = capacitance of the capacitor = 200 μF = 200 x 10⁻⁶ F
L = Inductance of the inductor = 120 mH = 0.12 H
f = frequency = 60 Hz
Capacitive reactance is given as
X = (2πfC)⁻¹
X = (2(3.14) (60) (200 x 10⁻⁶))⁻¹
X = 13.3 Ω
Inductive reactance is given as
X' = 2πfL
X' = 2(3.14) (60) (0.12)
X' = 45.2 Ω
Impedance of the circuit is given as
z = √(R² + (X' - X)²)
z = √(50² + (45.2 - 13.3)²)
z = 59.31 Ω
V = rms emf of the source = 240 Volts
rms voltage across the inductor is given as
V' = V z⁻¹ X'
V' = (240) (59.31)⁻¹ (45.2)
V' = 182.9 Volts
I think its C. because metal is a good conductor of heat
I hope this helps ^-^
let me know if im wrong
The answer is struggling to perform
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