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3 years ago

What is the full electron configuration for cadmium ?

Chemistry

1 answer:

rewona [7]3 years ago

6 0

Answer:

Electronic configuration, I've added a picture of this below.

Explanation:

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an atom of chlorine has an amount number of 17 and a mass number of 37. how many protons neutrons, and electrons are in the atom

Soloha48 [4]

Answer: There are 20 protons neutrons in the atom

6 0

2 years ago

The entropy change for a real, irreversible process is equal to:______.

taurus [48]

Answer:

The entropy change for a real, irreversible process is equal to zero.

The correct option is 'c'.

Explanation:

Lets look around all the given options -:

(a) the entropy change for a theoretical reversible process with the same initial and final states , since the entropy change is equal and opposite in reversible process , thus this option in not correct.

(b) equal to the entropy change for the same process performed reversibly ONLY if the process can be reversed at all. Since , the change is same as well as opposite too . Therefore , this statement is also not true .

(c) zero. This option is true because We generate more entropy in an irreversible process. Because no heat moves into or out of the surroundings during the procedure, the entropy change of the surroundings is zero.

(d) impossible to tell. This option is invalid , thus incorrect .

Hence , the correct option is 'c' that is zero.

8 0

3 years ago

A 0.1326 g sample of magnesium was burned in an oxygen bomb calorimeter. the total heat capacity of the calorimeter plus water w

Sladkaya [172]

Answer: Th enthalpy of combustion for the given reaction is 594.244 kJ/mol

Explanation: Enthalpy of combustion is defined as the decomposition of a substance in the presence of oxygen gas.

W are given a chemical reaction:

$Mg(s)+\frac{1}{2}O_2(g)\rightarrow MgO(s)$

$c=5760J/^oC$

$\Delta T=0.570^oC$

To calculate the enthalpy change, we use the formula:

$\Delta H=c\Delta T\\\\\Delta H=5760J/^oC\times 0.570^oC=3283.2J$

This is the amount of energy released when 0.1326 grams of sample was burned.

So, energy released when 1 gram of sample was burned is = $\frac{3283.2J}{0.1326g}=24760.181J/g$

Energy 1 mole of magnesium is being combusted, so to calculate the energy released when 1 mole of magnesium ( that is 24 g/mol of magnesium) is being combusted will be:

$\Delta H=24760.181J/g\times 24g/mol\\\\\Delta H=594244.3J/mol\\\\\Delta H=594.244kJ/mol$

4 0

3 years ago

Who else had to do a final model for the rust unit

ArbitrLikvidat [17]

Which one? Are u saying.

4 0

2 years ago

Type the correct answer in the box. a pharmacist works with a 1.75 m solution of sodium bromide (nabr) and water. the volume of

Elodia [21]

Answer: 147 mL

Explanation:

Given:

Molarity of the sodium bromide (NaBr) solution (M1) = 1.75 M

Volume of the solution (V1) = 84 mL

Molarity of the diluted NaBr solution (M2) = 1 M

Using the dilution formula to solve for V2:

$\begin{gathered}M_{1} V_{1}=M_{2} V_{2} \\V_{2}=(1.75 \mathrm{M} \times 84 \mathrm{~mL}) / 1 \mathrm{M} \\V_{2}=147 \mathrm{~mL}\end{gathered}$

Therefore, the new volume of the solution is 147 mL

8 0

2 years ago