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vladimir1956 [14]
4 years ago
5

molar mass of beryllium (Be) molar mass of silicon (Si) molar mass of calcium (Ca) molar mass of rhodium (Rh)

Chemistry
2 answers:
tankabanditka [31]4 years ago
5 0

Beryllium (Be):  9.01

Silicon (Si):  28.09

Calcium (Ca):  40.08

Rhodium (Rh): 102.91

(Basically the below answers just rounded off a bit:)

Options C, then C, then C, and then C) Ijust found out they were all option C!

Neko [114]4 years ago
3 0
Molarmass of beryllium is 9.0
molar mass of silicon is 28.4
molar mass of calcium is 40.1
molar mass of rhodium is 103.
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3 years ago
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Which of these elements exhibits chemical behavior similar to that of oxygen? select one:
scoray [572]
Answer:
            Sulfur (Option-C) <span>exhibits chemical behavior similar to that of oxygen.

Explanation:
                   Sulfur has same chemical properties as that of Oxygen because both of them belongs to same group in the periodic table. Also, the similarity of chemical behaviour among the group members is due to same number of electrons in their valence shells.
For examole, the electronic configuration of Oxygen is,

                                        1s</span>², 2s², 2p⁴

There are six valence electrons in the valence shell (i.e. 2) of Oxygen.

Now for Sulfur,
                                        1s², 2s², 2p⁶, 3s², 3p⁴

There are six valence electrons in the valence shell (i.e. 3) of Sulfur.

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3 0
4 years ago
Your dad is working on creating a brick border for the lake in your backyard each brick has a mass of 100 g and a volume of 20 c
wel

Answer:

5000kg/m³

Explanation:

density=mass/volume

d=m/v

d=100/20

=5g/cm³

g/cm³*1000=kg/m³

5g/m³*1000=5000kg/m³

4 0
3 years ago
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A gas is heated from 263.0 K to 298.0 K and the volume is increased from 24.0 liters to 35.0 liters by moving a large piston wit
Evgesh-ka [11]

Answer:

The answer to your question is   P2 = 0.78 atm

Explanation:

Data

Temperature 1 = T1 = 263°K                 Temperature 2 = T2 = 298°K

Volume 1 = V1 = 24 L                             Volume 2 = V2 = 35 L

Pressure 1 = P1 = 1                                  Pressure 2 = P2 = ?

Process

1.- To solve this problem use the Combined gas law

                          P1V1/T1 = P2V2/T2

-Solve for P2

                           P2 = P1V1T2 / T1V2

-Substitution

                          P2 = (1)(24)(298) / (263)(35)

-Simplification

                          P2 = 7152 / 9205

-Result

                          P2 = 0.777

   or                    P2 = 0.78 atm

5 0
4 years ago
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