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muminat
3 years ago
6

Find the no of moles of ca in 8g of ca​

Chemistry
1 answer:
Tom [10]3 years ago
4 0

Answer:

Thus,there are 0.2 mole in 8 g of calcium.

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What two states of matter are found during melting
kondaur [170]

Answer:

solid and liquid

Explanation:

6 0
3 years ago
A balloon with a volume of 2.0 L at 25°C is placed
Natali5045456 [20]

Answer:

V₂ = 2.1 L

Explanation:

Given data:

Initial volume of balloon = 2.0 L

Initial temperature = 25°C

Final temperature = 35°C

Final volume of balloon in hot room = ?

Solution:

Initial temperature = 25°C (25+273= 298 K)

Final temperature = 35°C (35+273 = 308 k)

According to this law, The volume of given amount of a gas is directly proportional to its temperature at constant number of moles and pressure.

Mathematical expression:

V₁/T₁ = V₂/T₂

V₁ = Initial volume

T₁ = Initial temperature

V₂ = Final volume  

T₂ = Final temperature

Now we will put the values in formula.

V₁/T₁ = V₂/T₂

V₂ = V₁T₂/T₁  

V₂ = 2.0 L × 308 K / 298 k

V₂ = 616 L.K / 298 K

V₂ = 2.1 L

3 0
3 years ago
. Copper(I) oxide, Cu2O, is reduced to metallic copper by heating in a stream of hydrogen gas. What mass of water is produced wh
maksim [4K]
Answer: 0.07868 mol H₂O

Explanation:

1) Chemical equation:

Cu₂O +H₂ → 2Cu + H₂O

2) mole ratios:

1 mol Cu₂O : 1 mol H₂ : 2 mol Cu : 1 mol H₂O

3) Convert 10.00 g of Cu to grams, using the atomic mass:

Atomic mass of Cu: 63.546 g/mol

number of moles = mass in grams / atomic mass = 10.00g / 63.546 g/mol

number of moles = 0.1574 mol

4) Use proportions

2mol Cu           0.1574 mol Cu
--------------- =  ---------------------
1 mol H₂O                   x

⇒ x = 0.1574 mol Cu × 1 mol H₂O / 2mol Cu = 0.07868 mol H₂O

That is the answer
7 0
3 years ago
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Iron(III) oxide and hydrogen react to form iron and water, like this:
Andru [333]

Answer:mmmm popeyes chicken

Explanation:

6 0
2 years ago
If 3.5 grams of NaN3 decomposed, how many grams of N2 would be produced?
Wewaii [24]

Answer:

5.25 moles.

Explanation:

The decomposition reaction of NaN₃ is as follows :

2NaN_3(s)\rightarrow 2Na(s)+3N_2(g)

We need to find how many grams of N₂ produced in the process.

From the above balanced chemical reaction, we conclude that the ratio of moles of sodium azide and nitrogen gas are 2 : 3.

2 moles of sodium azide decomposes to give 3 moles of nitrogen gas. So,

3.5 moles of sodium azide decomposes to give \dfrac{3}{2}\times 3.5=5.25 moles of nitrogen gas.

Hence, the number of moles produced is 5.25 moles.

6 0
2 years ago
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