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4 years ago

What is the charge and location of a neutron?

Chemistry

2 answers:

maksim [4K]4 years ago

7 0

Answer:

Neutrons give a neutral charg as in there name Neutron . ...

Neutrons are located with protons in the nucleus

Explanation:

Whitepunk [10]4 years ago

6 0

Answer:

There is no charge and it is in nucleus

Explanation:

the neutron is the nuetral one and the protron is positive charger and electron is negative. please let me know if you need me to explain more

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How many grams are there in 7.9 X 10^23 molecules of AgNO3?

DENIUS [597]

Answer:$$7.50 x 10^23$$

$$H_2SO_4$$?

Explanation:It is a fact that such a quantity has a mass of

98.08

⋅

. Why? Because

6.022

particles SPECIFIES a molar quantity. And we know (or can calculate) that sulfuric acid has a molar mass of

98.08

⋅

...

4 0

2 years ago

What mass of NaOH is in 250 mL of a 3.0M NaOH solution

Kay [80]

Answer:

about 30g

Explanation:

Molarity = mol/L

*convert mL to L*

3M=xmol/.25

xmol = .75

*convert to g

.75 mol NaOH * 40g/mol = 30 g

7 0

3 years ago

Read 2 more answers

State which of the following set of quantum number would be possible and which would be permissible for an electron in an atom.

raketka [301]

Answer:

The correct option is: e) n=4, l=3, $m_{l}$ = - 2 , $m_{s}$ = - 1/2

Explanation:

The four quantum numbers that describe the electrons in an atom are: The principal: n, azimuthal: l, magnetic: m, and spin: s.

For a given electron, the values of the quantum numbers should be in the given range- principal quantum number: n ≥ 1;

azimuthal quantum number: 0 ≤ l ≤ n − 1;

magnetic quantum number: −l ≤ $m_{l}$ ≤ +l;

spin quantum number: −s ≤ $m_{s}$ ≤ +s

Now, for n= 4,

The value of l: 0 to n − 1 = 0 to 3 = 0, 1, 2, 3

The value of $m_{l}$ for l= 3 : -3 to +3 = -3, -2, -1, 0, +1, +2, +3

The value of $m_{s}$ : -1/2, +1/2

Therefore, the given set of quantum numbers: n=4, l=3, $m_{l}$ = - 2 , $m_{s}$ = - 1/2; are possible and permissible for an electron in an atom.

5 0

3 years ago

5.00 ml of commercial bleach was diluted to 100.0 ml. 25.0 ml of the diluted sample was titrated with 4.56 ml of 0.100 m s2o3 2-

aev [14]

The solution would be like this for this specific problem:

4 NaOCl + S2O3{2-} + 2 OH{-} → 2 SO4{2-} + H2O + 4 NaCl

(0.00456 L) x (0.100 mol/L S2O3{2-}) x (4 mol NaOCl / 1 mol S2O3{2-}) x (100.0 mL / 25 mL) x 
(74.4422 g NaClO/mol) = 0.54313 g

(5.00 mL) x (1.08 g/mL) = 5.40 g solution

(0.54313 g) / (5.40 g) = 0.101 = 10.1%

So, the average percent by mass of NaClO in the commercial bleach is 10.1%.

3 0

3 years ago

A closed vessel system of volume 2.5 L contains a mixture of neon and fluorine. The total pressure is 3.32 atm at 0.0°C. When th

Oxana [17]

Answer: moles of Ne = 0.149 moles

moles of F₂ = 0.221 moles

Explanation:

The process occurs at costant volume.

Neon is a monoatomic gas, Cv =3/2R, Flourine is a diatomic gas, Cv = 5/2R

n = PV/RT ; where n is total = number of moles, P is total pressure = 3.32atm, V is volume = 2.5L, R is molar gas constant = 0.08206 L-atm/mol/K = 8.314 J/mol/K, T is temperature = 0.0°C = 273.15K

n(total) = (3.32 atm)(2.5 L)/(0.08206 L-atm/mol/K)(273.15) = 0.3703 mol

For one mole heated at constant volume,

Change in entropy, ∆S = ∫dq/T = ∫(Cv/T)dT

From T1 to T2, Cvln(T2/T2) = Cvln(288.15/273.15) = 0.05346•Cv

So, for 0.3703 moles,

∆S = (0.3703 mol)(0.05346)Cv = 0.345 J/K

⇒ Cv = 17.43 J/mol/K for the Ne/F₂ mixture.

For pure Ne, Cv = (3/2)R = 1.5 • 8.314 J/mol/K = 12.471 J/mol/K

For pure F₂, Cv = (5/2)R = 2.5 • 8.314 J/mol/K = 20.785 J/mol/K

If Y is the mole fraction of Ne, Y can be determined by setting the observed entropy change (∆S) to the weighted average of the entropy changes expected for the two different gases in the mixture:

17.43 J/mol/K = Y * 12.471 J/mol/K + (1 – Y) * 20.785 J/mol/K

⇒ 20.785 J/mol/K – 8.314 J/mol/K * Y = 17.43J/mol/K

Y = 0.403 ; 1 – Y = 0.597

moles of Ne = (0.403)(0.3703 mol) = 0.149 moles

moles of F₂ = (0.597)(0.3703 mol) = 0.221 moles

7 0

3 years ago