Answer:
![V=162L](https://tex.z-dn.net/?f=V%3D162L)
Explanation:
Hello,
In this case, we can compute the required volume by using the ideal gas equation as shown below:
![PV=nRT](https://tex.z-dn.net/?f=PV%3DnRT)
Thus, solving for the volume and considering absolute temperature (in Kelvins), we obtain:
![V=\frac{nRT}{P}= \frac{4.70mol*0.082\frac{atm*L}{mol*K}*(21+273)K}{0.700atm} \\\\V=162L](https://tex.z-dn.net/?f=V%3D%5Cfrac%7BnRT%7D%7BP%7D%3D%20%5Cfrac%7B4.70mol%2A0.082%5Cfrac%7Batm%2AL%7D%7Bmol%2AK%7D%2A%2821%2B273%29K%7D%7B0.700atm%7D%20%5C%5C%5C%5CV%3D162L)
Best regards.
A good feeling, but i'm not sure what it's called
Question:<u> As the sun heats the surface of the ocean, two layers of water result. What separates the layers.?</u>
Answer: <u>The Thermocline </u>
<em>Hope this helps!.</em>
<em>~~~~~~~~~~~~~~~~~~~</em>
<em>~A.W~ZoomZoom44</em>
Answer:
The answer is:
B
Explanation:
The compound in Option B is Methane.
Methane is known to be a compound which has two elements, carbon and hydrogen. It has a central atom which is surrounded by four hydrogen atoms. It's chemical formula is CH4.
Methane's outer atoms are dipoles and are in the same direction. This makes the overall molecule non-polar. The compound itself has non-polar bonds and it is non-polar itself.
Answer:
The answer to your question is 25.2 g of acetic acid.
Explanation:
Data
[Acetic acid] = 0.839 M
Volume = 0.5 L
Molecular weight = 60.05 g/mol
Process
1.- Calculate the number of moles of acetic acid
Molarity = moles / volume
-Solve for moles
moles = Molarity x volume
-Substitution
moles = (0.839)(0.5)
-Result
moles = 0.4195
2.- Calculate the mass of acetic acid using proportions and cross multiplications
60.05 g ----------------------- 1 mol
x ----------------------- 0.4195 moles
x = (0.4195 x 60.05) / 1
x = 25.19 g
3.- Conclusion
25.2 g are needed to prepare 0.500 L of Acetic acid 0.839M