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kati45 [8]
3 years ago
12

Which of the following explains the importance of the activation energy acting as a barrier for reactants? A:It prevents most re

actions from occurring spontaneously. B:It ensures the activated complexes remain stable. C:It allows energy to be released slowly from products. D: It stops the activated complexes from ever forming.
Chemistry
2 answers:
natita [175]3 years ago
7 0
A: It prevents most reactions from occurring spontaneously.

The answer above is correct.
IgorLugansk [536]3 years ago
3 0

Answer: Option (A) is the correct answer.

Explanation:

Activation energy is the minimum amount of energy required to carry out a chemical reaction.

So, when reactant molecules does not have the minimum amount of energy then they are not able to participate in a chemical reaction. Hence, the reaction does not take place.

Therefore, a catalyst acts as an initiator in this situation to carry out the reaction.

Thus, we can conclude that the importance of the activation energy acting as a barrier for reactants as it prevents most reactions from occurring spontaneously.

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uppose you are titrating an acid of unknown concentration with a standardized base. At the beginning of the titration, you read
sweet-ann [11.9K]

Answer:

V_{base}=18.00mL

Explanation:

Hello,

In this case, since you have both the final and initial volume for the titration procedure, clearly, the used volume is computed by the subtraction between them, since it accounts for the employed volume of the base, it turns out:

V_{base}=20.03mL-2.03mL\\\\V_{base}=18.00mL

Best regards.

4 0
3 years ago
Chlorine gas can be prepared in the laboratory by the reaction of hydrochloric acid with manganese(IV) oxide:You add 40.7 g of M
Alex787 [66]
:<span>  </span><span>4 HCl + MnO2 → MnCl2 + 2 H2O + Cl2 

(33.7 g MnO2) / (86.93691 g MnO2/mol) = 0.38764 mol MnO2 
(45.3 g HCl) / (36.4611 g HCl/mol) = 1.2424 mol HCl 

(a) 
1.2424 moles of HCl would react completely with 1.2424 x (1/4) = 0.3106 mole of MnO2, but there is more MnO2 present than that, so MnO2 is in excess and HCl is the limiting reactant. 

(b) 
(1.2424 mol HCl) x (1 mol Cl2 / 4 mol HCl) x (70.9064 g Cl2/mol) = 22.0 g Cl2 

(c) 
(77.7% of 22.0 g Cl2) = 17.1 g Cl2</span>
5 0
3 years ago
Malic acid, C4H6O5, has been isolated from apples. Because this compound reacts with 2 molar equivalents of base, it is a dicarb
Flura [38]

Answer and explanation:

The attached figure shows five different structures for the chemical formula C4H5O5, but only one of these structures represent the malic acid.

Malic acid is a dicarboxylic acid, this means malic acid has two

-COOH groups.  Also, malic acid is a secundary alcohol, which means it has a  R2-C-OH group.

-Structure A has two carboxylic groups, but it doesn´t have a secundary alcohol.

-Structure B doesn´t have any caborxylic group.

-Structure C has two carboxylic groups and  it is a secundary alcohol. Structure C is the Malic acid

4 0
3 years ago
Consider the following reaction:
ruslelena [56]

<u>Answer:</u> The rate of the reaction when concentrations are changed is 5.17\times 10^{-2}M/s

<u>Explanation:</u>

For the given chemical reaction:

A+B+C\rightarrow D

The given rate law of the reaction follows:

\text{Rate}_1=k\frac{[A][C]^2}{[B]^{1/2}}

We are given:

\text{Rate}_1=1.12\times 10^{-2}M/s

When the concentrations are changed:

New concentration of A = 2A  (Concentration is doubled)

New concentration of C = 2C   (Concentration is doubled)

New concentration of B = 3B     (Concentration is tripled)

The new rate law expression becomes:

\text{Rate}_2=k\frac{[2A][2C]^2}{[3B]^{1/2}}\\\\\text{Rate}_2=\frac{2\times 2^2}{3^{1/2}}\times (k\frac{[A][C]^2}{[B]^{1/2}})\\\\\text{Rate}_2=4.62\times (\text{Rate}_1)\\\\\text{Rate}_2=4.62\times 1.12\times 10^{-2}\\\\\text{Rate}_2=5.17\times 10^{-2}M/s

Hence, the rate of the reaction when concentrations are changed is 5.17\times 10^{-2}M/s

8 0
4 years ago
What is the relationship between kinetic energy and velocity ?
Harlamova29_29 [7]
Kinetic energy is directly proportional to the mass of the object and to the square of its velocity: K.E. = 1/2 m v2. If the mass has units of kilograms and the velocity of meters per second, the kinetic energy has units of kilograms-meters squared per second squared.
5 0
3 years ago
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